Where are the triangles so I can compare to find the triangle congruence?
Answer:
A linear function has the form y=mx+b
A line has a proportional relationship if y/x is always the same ratio for any value.
The slope m=(y2-y1)/(x2-x1) for some two points on a line is always constant, else it wouldn't create a line.
A line won't be proportional if you adapt b because the ratio of y/x won't match the slope anymore.
In the end this means all lines with proportional relationships must intersect (0,0) or in other words f(0)=0.
This happens if they have the shape y=mx.
Step-by-step explanation:
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Answer:
The sprinkler can spread water 18 feet away.
Step-by-step explanation:
We are given the following in the question:
Area formed by watering pattern = 1,017.36 square feet
We have to find the how far the sprinkler spread the water.
The sprinkler covers a circular area. We need to find the radius of this circular area to find the how far the sprinkler spread the water.
Area of circle =
where r is the radius of the circle.
Putting values, we get,
Thus, the sprinkler can spread water 18 feet away.
Answer:
5.75
Step-by-step explanation:
Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as
<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>
<span>Next, complete the square. </span>
<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>
<span>Also, for the x in the numerator </span>
<span>x = x + 1/2 - 1/2. </span>
<span>So </span>
<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>
<span>Integrate term by term to get </span>
<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>
<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>
<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>
<span>= 2 √(x) ln(x) - √(x) + C. </span>
<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>
<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>
<span>= arctan(e^x) + C.</span>
