How do i answer this question 5*(8-4)/4-2
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Considering the Central Limit Theorem, we have that:
a) The probability cannot be calculated, as the underlying distribution is not normal and the sample size is less than 30.
b) The probability can be calculated, as the sample size is greater than 30.
<h3>What does the Central Limit Theorem state?</h3>It states that the sampling distribution of sample means of size n is approximately normal has standard deviation , as long as the underlying distribution is normal or the sample size is greater than 30.
In this problem, the underlying distribution is skewed right, that is, not normal, hence:
- For item a, the probability cannot be calculated, as the underlying distribution is not normal and the sample size is less than 30.
- For item b, the probability can be calculated, as the sample size is greater than 30.
More can be learned about the Central Limit Theorem at brainly.com/question/16695444
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Answer:
Number of calls received in 1st evening = 24
Number of calls received in 2nd evening = 33
Number of calls received in 3rd evening = 72
Step-by-step explanation:
Let
number of calls received in first evening be "x"
number of calls received in 2nd evening be "y"
number of calls received in 3rd evening be "z"
Total, in 3 evenings, we have 129 phone calls, so we can write:
x + y + z = 129
3rd evening, 3 times as first evening. We can write:
z = 3x
2nd evening, 9 MORE THAN FIRST. So we can write:
y = 9 + x
Now we replace 2nd and 3rd equation in 1st equation to get:
x + y + z = 129
x + 9 + x + 3x = 129
Now, first, we solve for x:
Solving for y:
y = 9 + x
y = 9 + 24
y = 33
Solving for z:
z = 3x
z = 3(24)
z = 72
Thus,
Number of calls received in 1st evening = 24
Number of calls received in 2nd evening = 33
Number of calls received in 3rd evening = 72