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hichkok12 [17]
3 years ago
12

Would you rather have two 20% discount or a 40% discount?

Mathematics
2 answers:
yuradex [85]3 years ago
6 0

Answer:

Step-by-step 40%explanation:

zysi [14]3 years ago
5 0

Answer:2 20%

Step-by-step explanation: you can use it twice

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You have a jar of marbles. There are 15 red, 20 blue, 7 green, and 18 yellow marbles. You choose a marble at random from the jar
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the right answer is b. 2/3

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Math help questions <br>​
Evgen [1.6K]

After 1 year, the initial investment increases by 7%, i.e. multiplied by 1.07. So after 1 year the investment has a value of $800 × 1.07 = $856.

After another year, that amount increases again by 7% to $856 × 1.07 = $915.92.

And so on. After t years, the investment would have a value of \$800 \times 1.07^t.

We want the find the number of years n such that

\$856 \times 1.07^n = \$1400

Solve for n :

856 \times 1.07 ^n = 1400

1.07^n = \dfrac74

\log_{1.07}\left(1.07^n\right) = \log_{1.07}\left(\dfrac74\right)

n \log_{1.07}(1.07) = \log_{1.07} \left(\dfrac74\right)

n = \log_{1.07} \left(\dfrac74\right) = \dfrac{\ln\left(\frac74\right)}{\ln(1.04)} \approx \boxed{8.3}

4 0
2 years ago
Read 2 more answers
What is the slope intercept form of the equation of 6x+5y=-15
Soloha48 [4]
Slope intercept form is \sf y=mx+b, where 'm' is the slope and 'b' is the y-intercept.

\sf 6x+5y=-15

Subtract 6x to both sides:

\sf 5y=-6x-15

Divide 5 to both sides:

\boxed{\sf y=-\dfrac{6}{5}x-3}
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3 years ago
A used car was purchased in July 1999 for $11,900. If the car depreciates 13% of it's value each year, what is the value of the
trapecia [35]
1999 price = 11900
it depreciates 13%
\frac{13}{100} \times 11900 = 1547
year 2000 cost = 11900 - 1547 = 10353
it depreciates 13%
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year 2001 cost = 10353 - 1345.89 = 9007.11
it depreciates 13%
\frac{13}{100} \times 9007.11 = 1170.92
year 2002 cost = 9007.11 - 1170.92 = 7836.19
pls mark as brainliest
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Write a sine or cosine function for the data set
dmitriy555 [2]

Answer:

though this is difficult i know you would get it. Anyhow im real tired... will solve later... gl

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4 years ago
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