F(x)=x^3-7x-6 Since I don't have the graph and this is not a perfect cube, I will have to rely on Newton :P
x-(f(x)/(dy/dx))
x-(x^3-7x-6)/(3x^2-7)
(2x^3+6)/(3x^2-7), letting x1=0
0, -6/7, -.988, -.9999, -.99999999999, -1
(x^3-7x-6)/(x+1)
x^2 r -x^2-7x-6
-x r -6x-6
-6 r 0
(x+1)(x^2-x-6)=0
(x+1)(x-3)(x+2)=0
x= -2, -1, 3
Answer:
x=-12
Step-by-step explanation:
(-22 + 3x) /( 3x+7) =2
Multiply each side of the equation by 3x+7
-22+3x = 2(3x+7)
Then distribute
-22 +3x = 6x+14
Subtract 3x from each side
-22 = 3x+14
Subtract 14 from each side
-36 = 3x
Divide by 3
-12 =x
Answer:
Graph of the inequality x< -3 as shown below in the figure.
Step-by-step explanation:
Given the inequality: x < -3
Graph of this inequality as shown below in the figure.
All the points that are lie in the shaded area satisfy the equation x < -3 or
In other words, we can say that x can take any value less than -3 .
x ≠ -3 or any number that is greater than -3.
Since there is a strict inequality i.e x < -3 , the points that lie on the line x = -3 does not satisfy the equation.
Therefore, the dotted line is marked at x = -3
Unbelievably the same answer! Why? circumference is r * 2 * 3.14 = C
so i divided 12.56 with 3.14 = 4 / 2 = 2
the area of circle r^2 * 3.14 = A
2*2 = 4 * 3.14 is the same as circumference