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Colt1911 [192]
3 years ago
13

How much work is accomplished with a force of 250 in pushes about across the floor for this is a 50 m

Mathematics
1 answer:
Rzqust [24]3 years ago
6 0
As W=Fxd the perpendicular distance is 50m so 250x5 is equal to 1250 Joules
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