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3 years ago

6

Directions for making a quilt say to cut fifteen squares with sides that ate 3.625 inches long. What is the side lenght written

as a fraction?

2 answers:

ira [324]3 years ago

7 0

It would be 3 and 5/8 as a fraction.

Zigmanuir [339]3 years ago

6 0

Answer: The decimal length of the side of the squares (3.625 inches long) witten as a fraction is 3 5/8 inches long.

Solution:

3.625 = 3 0.625

3.625 = 3 0.625(1000)/1000

3.625 = 3 625/1000

3.625 = 3 (625/125) / (1000/125)

3.625 = 3 5/8

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The length of a rectangular garden is 6 more than its width. If the perimeter is 32 feet, what is the width and the area of the

PolarNik [594]

Answer:

${\fbox{ \sf{Width \: of \: a \: rectangular \: garden \: = 5 \: feet}}}$

$\boxed{ \sf{ \: Area \: of \: a \: rectangular \: garden = 55 {ft}^{2}}}$

Step-by-step explanation:

$\star$ Let the width of a rectangular garden be 'w'

$\star$ Length of a rectangular garden = 6 + w

$\star$ Perimeter of a rectangular garden = 32 feet

<u> $\longrightarrow$ </u><u> </u><u>Finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u> :

$\boxed{ \sf{ \: Perimeter \: of \: a \: rectangle \: = \: 2(length + width}}$

$\mapsto{ \text{32 = 2(6 + w + w)}}$

$\text{Step \: 1 \: : Collect \: like \: terms}$

Like terms are those which have the same base

$\mapsto{ \text{32 = 2(6 + 2w) }}$

$\text{Step \: 2 \: : Distribute \: 2 \: through \: the \: parentheses}$

$\mapsto{ \text{32 = 12 + 4w}}$

$\text{Step \: 3 \: : Swap \: the \: sides \: of \: the \: equation}$

$\mapsto{ \text{4w + 12 = 32}}$

$\text{Step \: 4 \: : Move \: 12 \: to \: right \: hand \: side \: and \: change \: its \: sign}$

$\mapsto{ \text{4w = 32 - 12}}$

$\text{Step \: 5 \: : Subtract \: 12 \: from \: 32}$

$\mapsto{ \sf{4w = 20}}$

$\text{Step \: 6 \: : Divide \: both \: sides \: by \: 4}$

$\mapsto{ \sf{ \frac{4w}{4} = \frac{20}{4}}}$

$\text{Step \: 7 \: : Calculate}$

$\mapsto{ \text{w = 5}}$

Width of a rectangular garden = 5 feet

$\longrightarrow$ <u>Substituting </u><u>/</u><u> </u><u>Replacing </u><u>the </u><u>value </u><u>of </u><u>w </u><u>in </u><u>6</u><u> </u><u>+</u><u> </u><u>w </u><u>in </u><u>order </u><u>to </u><u>find</u><u> </u><u>the</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular </u><u>garden</u>

$\mapsto{ \sf{Length = 6 + w = 6 + 5 = \bold{11 \: feet} }}$

$\longrightarrow$ <u>Finding</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangular</u><u> </u><u>garden</u><u> </u><u>having</u> <u>length of 11 feet and</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>5</u><u> </u><u>feet</u> :

$\boxed{ \sf{Area \: of \: a \: rectangle = length \:∗ \: width}}$

$\mapsto{ \text{Area \: = \: 11 \: ∗ \: 5}}$

$\mapsto{ \sf{Area \: = 55 \: {ft}^{2} }}$

Area of a rectangular garden = 55 ft²

Hope I helped!

Best regards! :D

~ $\sf{TheAnimeGirl}$

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