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romanna [79]
3 years ago
7

Abdul, while driving to school, computes the average speed for his trip to be 20 km/hr. On his return trip along the same route,

there is less traffic and the average speed is 40km/hr. What is the average sped for Abdul's trip?
Mathematics
1 answer:
gulaghasi [49]3 years ago
8 0
You need to find the total distance and the total time. The total distance is two times the distance to school, 2d.s=d/t=>t=d/sWhere s is speed, d is distance and t is time. So the time taken to get to school is:d/s1and the time taken to get back is:d/s2so the total time is:d/s1+d/s2=d(1/s1+1/s2)So, as speed = distance/time, divide the total distance by the total time:2d/d(1/s1+1/s2)=2/(1/s1+1/s2)=2/(1/20+1/40)=80/3≈26.7km/hr
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Answer:

32 gallons

Step-by-step explanation:

c'mon this is simple, but thx for the points

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3 years ago
Using sigma notation write the geographic series: 6+12+24+48+96
Alika [10]

Answer:

$$\sum_{n=1}^{5} 6(2^{n-1}) $$

Step-by-step explanation:

6 + 12 + 24 + 48 + 96 =

= 6 + 6 * 2 + 6 * 4 + 6 * 8 + 6 * 16

= 6 + 6 * 2^2 + 6 * 2^2 + 6 * 2^3 + 6 * 2 * 4

= 6 * 2^(n - 1)

$$\sum_{n=1}^{5} 6(2^{n-1}) $$

4 0
3 years ago
it confuses me when i have to fill in the in between i just dont quite understand how to work it out please explain it clearly
prisoha [69]

<em>Make the unknown numerator be x and unkown denominotor be y</em>

<em>We have :  7 - </em>\frac{x}{y} = 6\frac{4}{5}

            =>       \frac{x}{y} = 7 - 6\frac{4}{5}

                       \frac{x}{y} = \frac{1}{5}

<em>So we need to fill in the box :</em> \frac{1}{5}

<em>If the answer is helpful, Brainliest please!</em>

8 0
3 years ago
How do I solve question 6 through 8?<br> Solve for me
rewona [7]

The equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

<h3>How to determine the functions?</h3>

A quadratic function is represented as:

y = a(x - h)^2 + k

<u>Question #6</u>

The vertex of the graph is

(h, k) = (-1, 2)

So, we have:

y = a(x + 1)^2 + 2

The graph pass through the f(0) = -2

So, we have:

-2 = a(0 + 1)^2 + 2

Evaluate the like terms

a = -4

Substitute a = -4 in y = a(x + 1)^2 + 2

y = -4(x + 1)^2 + 2

<u>Question #7</u>

The vertex of the graph is

(h, k) = (2, 1)

So, we have:

y = a(x - 2)^2 + 1

The graph pass through (1, 3)

So, we have:

3 = a(1 - 2)^2 + 1

Evaluate the like terms

a = 2

Substitute a = 2 in y = a(x - 2)^2 + 1

y = 2(x - 2)^2 + 1

<u>Question #8</u>

The vertex of the graph is

(h, k) = (1, -2)

So, we have:

y = a(x - 1)^2 - 2

The graph pass through (0, -3)

So, we have:

-3 = a(0 - 1)^2 - 2

Evaluate the like terms

a = -1

Substitute a = -1 in y = a(x - 1)^2 - 2

y = -(x - 1)^2 - 2

Hence, the equations of the functions are y = -4(x + 1)^2 + 2, y = 2(x - 2)^2 + 1 and y = -(x - 1)^2 - 2

Read more about parabola at:

brainly.com/question/1480401

#SPJ1

5 0
2 years ago
3x-5y+6 how many terms are in this expression
djyliett [7]
3 terms are in the expression
7 0
3 years ago
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