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romanna [79]
3 years ago
7

Abdul, while driving to school, computes the average speed for his trip to be 20 km/hr. On his return trip along the same route,

there is less traffic and the average speed is 40km/hr. What is the average sped for Abdul's trip?
Mathematics
1 answer:
gulaghasi [49]3 years ago
8 0
You need to find the total distance and the total time. The total distance is two times the distance to school, 2d.s=d/t=>t=d/sWhere s is speed, d is distance and t is time. So the time taken to get to school is:d/s1and the time taken to get back is:d/s2so the total time is:d/s1+d/s2=d(1/s1+1/s2)So, as speed = distance/time, divide the total distance by the total time:2d/d(1/s1+1/s2)=2/(1/s1+1/s2)=2/(1/20+1/40)=80/3≈26.7km/hr
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you are given numbers, {30 + n, n/3, square root n+16}. Find the smallest value of n so that all of the numbers in the set are n
Juli2301 [7.4K]
<h3>Answer:   n = 9</h3>

========================================================

Explanation:

Let's assume that n is not negative. If we tried the smallest nonnegative value, n = 0, then we get

  • 30+n = 30+0 = 30
  • n/3 = 0/3 = 0
  • sqrt(n+16) = sqrt(0+16) = 4

The middle result 0 isn't a natural number. The set of natural numbers is {1,2,3,4,...} which is the set of positive whole numbers.

So we can't use n = 0.

Through trial and error, you should find that n = 9 is the next value we can try such that sqrt(n+16) is a natural number, and so is n/3.

If n = 9, then,

  • 30+n = 30+9 = 39
  • n/3 = 9/3 = 3
  • sqrt(n+16) = sqrt(9+16) = 5

We see that the middle result is now larger than 0 and it's a natural number. The same can be said for the last result as well.

7 0
3 years ago
Pls help me. Pic is attached below
Mademuasel [1]

Answer:

90

Step-by-step explanation:

3b/3=180/3

then u simplify

ur answer will be

b=90

4 0
3 years ago
The length of a rectangle is increasing at a rate of and its width is increasing at a rate of . when the length is 20 cm and the
pav-90 [236]

<span><span>220<span> cm2</span>/s </span>
 EXPLINATION</span>

L length of rectangel (cm)

W width of rectangel(cm)

A area of rectangel (cm²)

T time (s)

we are told that:

d1\dt=8cm\s(const),and dw\dt =3cm\s(const)

the area of the rectangel is

A=LW

Differentiating wrt t (using the product rule) we get;

<span><span><span>dA</span><span>dt</span></span>=<span>(l)</span><span>(<span><span>dw</span><span>dt</span></span>)</span>+<span>(<span><span>dl</span><span>dt</span></span>)</span><span>(w)</span></span>

∴<span><span>dA</span><span>dt</span></span>=3l+8w

So when <span>l=20</span><span> and </span><span>w=10⇒</span>
<span>     <span><span>dA</span><span>dt</span></span>=3⋅20+8⋅20</span>
<span>∴<span><span>dA</span><span>dt</span></span>=60+160</span>
<span>∴<span><span>dA</span><span>dt</span></span>=220<span> cm2</span>/<span>s</span></span>

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fredd [130]

Answer:

Step-by-step explanation: 4.6 grams?

7 0
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The answer to this question is
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