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Hoochie [10]
3 years ago
10

Please Please help!

Mathematics
1 answer:
sergiy2304 [10]3 years ago
8 0
They are vertical angles and congruent angles.
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Can someone solve this?
serg [7]

Answer:

i think its c for the first one and d for the 2nd

Step-by-step explanation:

this is what i got but it might be wrong

7 0
4 years ago
What is this I need help
77julia77 [94]
If it is homework i cant help you
sorry

5 0
3 years ago
Question 3 < > In a particular class of 33 students, 18 are men. What fraction of the students in the class are women?​
Juli2301 [7.4K]

Answer:

Your answer is 15 Women

Step-by-step explanation:

33-18= 15

8 0
2 years ago
Explain the difference between using the tangent ratio to solve for a missing angle in a right triangle versus using the cotange
Lena [83]

Answer:

While determining the angle \theta with the tangent ratio or cotangent ratio uses the same sides lengths but the ratios are inverse of each other.

Step-by-step explanation:

See the diagram attached.

Let us assume a right triangle Δ ABC with ∠ B = 90°. Now, assume that the angle ∠ CAB = \theta and the sides AB, BC, CA are 3, 4, 5 units respectively.

The tangent ratio of an angle \theta is given by  

\tan \theta = \frac{BC}{AB} = \frac{4}{3}  

Again, the cotangent ratio of angle \theta is given by  

\cot \theta = \frac{AB}{BC} = \frac{3}{4}  

Therefore, in both the cases of tangent ratio and cotangent ratio are inverse of each other and while determining the angle \theta with the tangent ratio or cotangent ratio uses the same sides lengths but the ratios are inverse of each other. (Answer)

4 0
4 years ago
f of x equals the quantity x minus one times the quantity x plus two times the quantity x plus four all divided by the quantity
Alik [6]
f(x)=\frac{(x-1)(x+2)(x+4)}{(x+1)(x-2)(x-4)}

The denominator of a fraction can't be equal to 0.
(x+1)(x-2)(x-4) \not= 0 \\
x+1 \not=0 \ \land \ x-2 \not= 0 \ \land \ x-4 \not= 0 \\
x \not= -1 \ \land \ x \not = 2 \ \land \ x \not= 4

The function is undefined at x=-1, x=2, x=4, because for these values the denominator of the function would equal 0, and it's impossible to divide by 0.

Edward is correct.
7 0
4 years ago
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