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3 years ago

10

Please Please help!

1 answer:

sergiy2304 [10]3 years ago

8 0

They are vertical angles and congruent angles.

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The equation r(t)= (2t)i + (2t-16t^2)j is the position of a particle in space at time t. Find the angle between the velocity and

ankoles [38]

Answer:

The answer is 135 degrees.

Step-by-step explanation:

As we are given the position. If we take the <u>derivative</u>, we get the velocity vector. If we take the <u>derivative</u> again, we find the acceleration vector of the particle.

$r(t)=(2t)i+(2t-16t^{2})j$

$V(t)=2i+(2-32t)j$

$a(t)=-32j$

At time t=0;

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$a(t)=-32j$

As i attach in the picture the angle between the velocity and acceleration vector is $(45+90)=135$ degrees

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Step-by-step explanation:

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