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3 years ago

Write a relate substraction fact 6+8=14

Mathematics

2 answers:

vlabodo [156]3 years ago

8 0

14-8=6. Take the total and subtract the 8.

ad-work [718]3 years ago

7 0

21-7=14 is a relate subtraction problem

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In the diagram, g ∥ h, m∠1 = (4x + 36)°, and m∠2 = (3x – 3)°. What is the measure of ∠3? 21° 60° 120° 159°

cricket20 [7]

M<2 = m<3
but
m<1 + m<2 = 180
4x + 36 + 3x – 3 = 180
7x + 33 = 180
7x = 147
x = 21

m<2 = 3x – 3
m<2 = 3(21) - 3
m<2 = 63 - 3
m< 2 = 60

m<3 = m<2 = 60

answer
60°

4 0

3 years ago

The gardening club at school is growing vegetables. The club has 300 square feet of planting beds. Cucumber plants require 6 squ

nadya68 [22]

The question doesn't ask anything in particular, I will show the set of inequalities defined in the problem.

Answer:

System of inequalities:

$6c+4t\leq 300$

$c>0\\t > 0\\c+t\geq 60$

Step-by-step explanation:

Inequalities

The express relations between expressions with a sign other than the equal sign. Common relationals are 'less than', 'greater than', 'not equal to', and many others.

The gardening club at school has 300 square feet of planting beds to plant cucumber and tomato. Each cucumber plant requires 6 square feet of growing space and each tomato plant requires 4 square feet of growing space. We know the total area cannot exceed 300 square feet, so

$6c+4t\leq 300$

Being c and t the number of cucumber and tomato plants respectively.

We also know the students want to plant some of each type of plant and have at least 60 plants. This lead us to more conditions

$c>0\\t > 0\\c+t\geq 60$

Note: The set of inequalities shown is not enough to uniquely solve the problem. We need something to maximize or minimize to optimize c and t

8 0

3 years ago

Use the discriminant to determine what type of roots the equations will have, and categorize the equations according to their ro

topjm [15]

Step-by-step explanation:

The discriminant of the quadratic equation $ax^2+bx+c=0$ :

$\Delta=b^2-4ac$

If Δ < 0, then the equation has two complex roots $x=\dfrac{-b\pm\sqrt\Delta}{2a}$

If Δ = 0, then the equation has one repeated root $x=\dfrac{-b}{2a}[/tex If Δ > 0, then the equation has two discint roots [tex]x=\dfrac{-b\pm\sqrt\Delta}{2a}$

$1.\ x^2-4x+2=0\\\\a=1,\ b=-4,\ c=2\\\\\Delta=(-4)^2-4(1)(2)=16-8=8>0,\ \bold{two\ distinct\ roots}\\\sqrt\Delta=\sqrt8=\sqrt{4\cdot2}=2\sqrt2\\\\x=\dfrac{-(-4)\pm2\sqrt2}{2(1)}=\dfrac{4\pm2\sqrt2}{2}=2\pm\sqrt2\\\\==============================\\\\2.\ 5x^2-2x+3=0\\\\a=5,\ b=-2,\ c=3\\\\\Delta=(-2)^2-4(5)(3)=4-60=-56$

$3.\ 2x^2+x-6=0\\\\a=2,\ b=1,\ c=-6\\\\\Delta=1^2-4(2)(-6)=1+48=49>0,\ \bold{two\ distinct\ roots}\\\sqrt\Delta=\sqrt{49}=7\\\\x=\dfrac{-1\pm7}{(2)(2)}\\\\x_1=\dfrac{-8}{4}=-2,\ x_2=\dfrac{6}{4}=\dfrac{3}{2}\\\\==============================\\\\4.\ 13x^2-4=0\qquad\text{add 4 to both sides}\\\\13x^2=4\qquad\text{divide both sides by 13}\\\\x^2=\dfrac{4}{13}\to x=\pm\sqrt{\dfrac{4}{13}},\ \bold{two\ distinct\ roots}\\\\==============================$

$5.\ x^2-6x+16=0\\\\a=1,\ b=-6,\ c=16\\\\\Delta=(-6)^2-4(1)(16)=36-64=-28$

$7.\ 4x^2+11=0\qquad\text{subtract 11 from both sides}\\\\4x^2=-11\qquad\text{divide both sides by 4}\\\\x^2=-\dfrac{11}{4}\to x=\pm\sqrt{-\dfrac{11}{4}}\\\\x=\pm\dfrac{\sqrt{11}}{2}\ i,\ \bold{two\ complex\ roots}$

6 0

3 years ago

Read 2 more answers

William is planning a party. He spent $110.74 to buy 9.8 pounds of candy for favors. What was the cost per pound of the candy? (

AfilCa [17]

Answer: $11.30 per pound

Step-by-step explanation:

William spent $110.74 to buy 9.8 pounds of candy.

To find the cost per candy, divide the amount spent by the quantity of candy:

=Amount spent on candy / Quantity of candy

= 110.74 / 9.8

= $11.30 per pound

6 0

3 years ago

Find the surface area of the rectangular prism

Zielflug [23.3K]

Answer:

A=556

Step-by-step explanation:

lxwxh

5 0

3 years ago