
⇰Let O be the point of observation on the ground OX.
⇰Let A and B be the two positions of the jet.

















![\bf[ \boxed{➯OM=OL+LM=OL+AB=(x+3000)m \: and \: BM=h \: m]}](https://tex.z-dn.net/?f=%20%5Cbf%5B%20%5Cboxed%7B%E2%9E%AFOM%3DOL%2BLM%3DOL%2BAB%3D%28x%2B3000%29m%20%20%5C%3A%20and%20%5C%3A%20BM%3Dh%20%5C%3A%20m%5D%7D)


⇰ Equating the value of x from (1) and (2),we get;





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Answer:
25
Explanation:
the normal range would be 24.9 and 25 is the closest answer. Sorry i did not answer sooner.
True Because if you think about it , it makes total sense
Answer:
it is important to see children as soon as they arrive to the office because it is necessary to see the condition of children like health,diet....everyday
The correct answer is C.)
Carbon Monoxide, a by product and a pollutant, when inhaled replaces oxygen which in turn devastates the body. It affects the heart directly by stopping the oxygen flow which in turn reduces the pumping capacity and can permanently impair it's cardiac function.
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