30 x 0.75 = 22.5 .............(1st)
22.5 x 0.75 = 16.875 ......(2nd)
16.875 x 0.75 = 12.66 ....(3rd)
ANSWER: C) 12.66
Answer:
20 longs, 9 units more than the 9 flats
Step-by-step explanation:
If Abby has 9 flats, she has 900 blocks of the 1109 she needs. The remaining 209 can be represented by ...
20 longs
9 units
_____
<em>Comment on the question</em>
We cannot see the model Abby has put together so far, so we don't know exactly what it takes to finish it. Any longs or units she already shows must be subtracted from the numbers above.
Step-by-step explanation:
![(x - 4)(x + 2) = 16 \\ {x}^{2} + (- 4 + 2)x + ( - 4) \times 2= 16 \\ {x}^{2} - 2x - 8 - 16 = 0 \\ {x}^{2} - 2x - 24 = 0 \\ is \: the \: standard \: form.](https://tex.z-dn.net/?f=%28x%20-%204%29%28x%20%2B%202%29%20%3D%2016%20%5C%5C%20%20%7Bx%7D%5E%7B2%7D%20%20%2B%20%28-%204%20%2B%202%29x%20%2B%20%28%20-%204%29%20%20%5Ctimes%202%3D%2016%20%5C%5C%20%20%7Bx%7D%5E%7B2%7D%20%20-%202x%20-%208%20%20-%2016%20%3D%200%20%5C%5C%20%20%7Bx%7D%5E%7B2%7D%20%20-%202x%20-%2024%20%3D%200%20%5C%5C%20is%20%5C%3A%20the%20%5C%3A%20standard%20%5C%3A%20form.)
![\text{The length of the diagonal is }11.2\text{ mm}](https://tex.z-dn.net/?f=%5Ctext%7BThe%20length%20of%20the%20diagonal%20is%20%7D11.2%5Ctext%7B%20mm%7D)
Here, we want to find the diagonal of the given solid
To do this, we need the appropriate triangle
Firstly, we need the diagonal of the base
To get this, we use Pythagoras' theorem for the base
The other measures are 6 mm and 8 mm
According ro Pythagoras' ; the square of the hypotenuse equals the sum of the squares of the two other sides
Let us have the diagonal as l
Mathematically;
![\begin{gathered} l^2=6^2+8^2 \\ l^2\text{ = 36 + 64} \\ l^2\text{ =100} \\ l\text{ = }\sqrt[]{100} \\ l\text{ = 10 mm} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20l%5E2%3D6%5E2%2B8%5E2%20%5C%5C%20l%5E2%5Ctext%7B%20%3D%2036%20%2B%2064%7D%20%5C%5C%20l%5E2%5Ctext%7B%20%3D100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%20%7D%5Csqrt%5B%5D%7B100%7D%20%5C%5C%20l%5Ctext%7B%20%3D%2010%20mm%7D%20%5Cend%7Bgathered%7D)
Now, to get the diagonal, we use the triangle with height 5 mm and the base being the hypotenuse we calculated above
Thus, we calculate this using the Pytthagoras' theorem as follows;
Question 1:
Since the triangles are congruent, we know that QS = TV
This means that
3v + 2 = 7v - 6
Subtract both sides by 2
3v = 7v - 8
Subtract 7v from both sides
-4v = -8
Divide both sides by -4
v = 2
Plug this value back into 3v + 2 and you get 8.
QS = 8
Since the triangles are congruent
QS = 8 AND TV = 8
Question 2:
So we know that AC = AC because that's a shared side.
It's also given that BC = CD.
In order for two triangles to be congruent by SAS, the angle between the two sides must be congruent.
That means angle C must be congruent to angle C from the other triangle.
Question 3:
We know that AC = AC because it's a shared side.
We also know that angle A from one triangle is equal to angle C from the other.
However, for a triangle to be congruent by SAS, the congruent angle must be between two congruent sides.
In order for us to prove congruence by SAS, AD must be congruent to BC.
Have an awesome day! :)