3 years ago

Which equation represents a line that has a slope of 1/3 and passes through point (–2, 1)?

Mathematics

1 answer:

Yuliya22 [10]3 years ago

6 0

Answer:

The equation would be y - 1 = 1/3(x + 2)

Step-by-step explanation:

In order to find this, we simply plug the values we have into point slope form.

y - y1 = m(x - x1)

y - 1 = 1/3(x - -2)

y - 1 = 1/3(x + 2)

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What is the equation of the line that passes through the points (-3,5) (6,8)

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$(\stackrel{x_1}{-3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{8}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{(-3)}}}\implies \cfrac{3}{6+3}\implies \cfrac{3}{9}\implies \cfrac{1}{3}$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{(-3)}) \\\\\\ y-5=\cfrac{1}{3}(x+3)\implies y-5=\cfrac{1}{3}x+1\implies y=\cfrac{1}{3}x+6$