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3 years ago

Which equation represents a line that has a slope of 1/3 and passes through point (–2, 1)?

Mathematics

1 answer:

Yuliya22 [10]3 years ago

6 0

Answer:

The equation would be y - 1 = 1/3(x + 2)

Step-by-step explanation:

In order to find this, we simply plug the values we have into point slope form.

y - y1 = m(x - x1)

y - 1 = 1/3(x - -2)

y - 1 = 1/3(x + 2)

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3 years ago

Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(

Inessa05 [86]

Answer:

$2+i$

Step-by-step explanation:

Given the expression:

$\dfrac{4+\sqrt{16-(4)(5)}}{2}$

To find:

The expression of above complex number in standard form $a+bi$ .

Solution:

First of all, learn the concept of $i$ (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by $i$ .

Value of $i =\sqrt{-1}$ .

Now, let us consider the given expression:

$\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i$

So, the given expression in standard form is $2+i$ .

Let us compare with standard form $a+bi$ so we get $a =2, b =1$ .

$\therefore$ The standard form of

$\dfrac{4+\sqrt{16-(4)(5)}}{2}$

is: $\bold{2+i}$

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