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kumpel [21]
3 years ago
12

3. A group of workers is harvesting berries at a constant rate. An equation that represents the number of baskets of berries the

workers picked over a period of time, in hours, is y = 2x + 15. (a) What are the slope and the y-intercept for the equation that represents the number of baskets of berries the workers picked over a period of time? (b) What are the rate of change (slope) and the initial amount (y-intercept)? Explain the meaning of the rate of change and the initial amount for the situation. Answer in complete sentences
Mathematics
1 answer:
grin007 [14]3 years ago
6 0

In y = mx + b form, the slope can be found in the m position and the y intercept can be found in the b position.



y = mx + b


y = 2x + 15


slope(m) = 2 and y int (b) = 15



The initial amount is the y intercept, which is 15. The rate of change (the slope) is 2


example :  


baskets picked in 1 hr :


y = 2(1) + 15


y = 2 + 15


y = 17



baskets  picked in 2 hrs :


y = 2(2) + 15


y = 4 + 15


y = 19



so the slope ( rate of change) is basically saying for every hr of picking, you pick 2 baskets...so your picking 2 baskets per hr.


The y intercept (15) is telling us that they already had 15 baskets to start with.

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Find dy/dx by implicit differentiation for ysin(y) = xcos(x)
tatyana61 [14]

Answer:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

Step-by-step explanation:

So we have:

y\sin(y)=x\cos(x)

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]

Let's do each side individually.

Left Side:

We have:

\frac{d}{dx}[y\sin(y)]

We can use the product rule:

(uv)'=u'v+uv'

So, our derivative is:

=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]

We must implicitly differentiate for y. This gives us:

=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]

For the sin(y), we need to use the chain rule:

u(v(x))'=u'(v(x))\cdot v'(x)

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})

Simplify:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}

And we are done for the right.

Right Side:

We have:

\frac{d}{dx}[x\cos(x)]

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]

Differentiate:

=\cos(x)-x\sin(x)

So, our entire equation is:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

And we're done!

5 0
3 years ago
Jess will plant up to 27 acres on her farm with wheat and corn. More than 5 acres will be planted with wheat.
Lena [83]
The first thing we do in these cases is to define the variables.
 We have then:
 w = represent the number of acres of wheat
 c = represent the number of acres of corn
 We write now the inequalities based is:
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 w + c <= 27
 "More than 5 acres will be planted with wheat"
 w> 5
 Answer:
 
two inequalities that represent this situation are:
 
w + c <= 27
 
w> 5
8 0
3 years ago
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ABCD diagonals intersect at E. If m∠BAC=4x+5 and m∠CAD=5x-14, then find m∠CAD.
Travka [436]

Answer: m∠CAD = 81°

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ABCD is a prallelogram. One property of diagonal in a parallelogram is it separates the parallelogram in 2 congruent triangles.

The figure below shows ABCD with its diagonals.

Since diagonal divides a parallelogram in 2 congruent triangles, it means the internal angles are also congruent. So

m∠BAC = m∠CAD

4x + 5 = 5x - 14

x = 19

Then, m∠CAD is

m∠CAD = 5(19) - 14

m∠CAD = 81

The angle m∠CAD is 81°.

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Aleks04 [339]

Answer:

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GarryVolchara [31]
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