Answer:
Step-by-step explanation:
step 1
we have the points
(-1,0), (-2,0), and (0,2)
Plot the points
using a graphing tool
see the attached figure
The graph of a quadratic function must be a vertical parabola open upward
The vertex is a minimum
The quadratic function in general form is equal to
Substitute the value of x and the value of y of each given ordered pair in the general equation and solve for a,b and c
(0,2)
For x=0, y=2
substitute
(-1,0)
For x=-1, y=0
substitute
----> 
----> equation A
(-2,0)
For x=-2, y=0
substitute
----> equation B
we have the system
----> equation A
----> equation B
substitute equation A in equation B
solve for b
Find the value of a
therefore
The quadratic function in general form is equal to
see the attached figure N 2 to better understand the problem
X•X•X•X•X•X•X•X•X•X
That is the answer for your problem
We know that if two lines are Perpendicular then Product of Slopes of both of these Perpendicular lines should be Equal to -1
Given : Equation of 1st Perpendicular line is -x + 3y = 9
This can be written as :
3y = x + 9
y = x/3 + 3
Comparing with standard form : y = mx + c
we can notice that slope of 1st Perpendicular line = 1/3
Slope of 1st Line × Slope of 2nd line = -1
1/3 × Slope of 2nd line = -1
Slope of 2nd line = -3
We know that the form of line passing through point (x₀ , y₀) and having slope m is :
y - y₀ = m(x - x₀)
Here the 2nd Perpendicular line passes through the point (-3 , 2)
x₀ = -3 and y₀ = 2 and we found m = -3
⇒ y - 2 = -3(x + 3)
⇒ -3x - 9 = y - 2
⇒ -3x - y = 7
Answer:
- R ⇔ T
- S ⇔ X
- T ⇔ Y
- RS ⇔ TX
- RT ⇔ TY
- ST ⇔ XY
Step-by-step explanation:
Corresponding parts are listed in the same order in the congruence statement:
RST ≅ TXY
R ⇔ T
S ⇔ X
T ⇔ Y
RS ⇔ TX
RT ⇔ TY
ST ⇔ XY
_____
Above, we have used ⇔ to mean "corresponds to."
