((32/5)f)/d^3
hope this helps
The answer will be D) 75
To find this it’s easiest to find how many animals there are per percent. So to find this you simply have to divide 30 (the number of cats) by 40 (the percent that makes up) to find the number of animals per percent.
30/40
.75
Then you multiply this by 100 to find how many animals there are total.
.75(100)
75
Answer:
13.1666666667 or 13.17
Step-by-step explanation:
The mean is the average of the numbers. So you should add 16, 12, 16, 8, 14, and 13. When you add all of these up, you get 79. Then, you divide 79 by the number of numbers there are. Since there are 6 cats, there are 6 numbers. 79 divided by 6 equals 13.1666666667. Now we round the number to the nearest tenth and we will get 13.17.
Answer: 10⁻⁸°⁹
<u>Step-by-step explanation:</u>
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Any value which is more than 2 standard deviations away from the mean is considered to be "unusual."
2 standard deviations above the mean 52.4 mp would be 52.4+2(1.8), or 56; 2 std devs below the mean would be 52.4 - 2(1.8), or 48.8. Thus, any value larger than 56 or any value smaller than 48.8 would be "unusual."
54.8, 49.1 and 51.3 are not unusual; 56.5 is unusual, because it's greaster than 56.
