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Lyrx [107]
2 years ago
14

Admission to a fair of $5.00 and going on r rides that cost $2.00 each.

Mathematics
2 answers:
postnew [5]2 years ago
6 0
It depends on how many rides you going to get on.
svet-max [94.6K]2 years ago
5 0
? Is this even an quiestion
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F(n) =7n -11 <br> f(1)<br> f(2)
UkoKoshka [18]

Answer:

- 4 and 3

Step-by-step explanation:

Given

f(n) = 7n - 11

To evaluate f(1) and f(2) substitute n = 1 and n = 2 into f(n), that is

f(1) = 7(1) - 11 = 7 - 11 = - 4

f(2) = 7(2) - 11 = 14 - 11 = 3

5 0
2 years ago
Is 0.212121212121...a rational number because a irrational number does not terminate or repeat?
pentagon [3]
The 21 part repeats

it can be represented as 21/99

it's rational
8 0
2 years ago
LaShawn earned $60.00 for working 8 hours this weekend. What is the total amount of money LaShawn would earn for working 34 hour
lora16 [44]

To find this answer we have to do these steps below

1. Find the amount of money that LaShawn earns in an Hour

We have to do 60/8 which is 7.5

LaShawn earns 7.5 dollars in an hour

2. Multiply 7.5 by 35

The answer to that is 262.5 dollars

Therefore the answer is 262.5 dollars

I hope this helped, if it's wrong, blame me

Ps. Brailents would help a LOT

7 0
2 years ago
A newspaper poll asked respondents if they trusted "eco friendly" labels on cleaning products. Out of 1000 adults surveyed, 498
Paul [167]

Answer:

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of respondents that trust these labels is not significanlty less than 0.5 or 50%.  

Step-by-step explanation:

1) Data given and notation

n=1000 represent the random sample taken

X=498 represent the adults that trust these labels

\hat p=\frac{498}{1000}=0.498 estimated proportion of respondents that trust these labels

p_o=0.5 is the value that we want to test

\alpha represent the significance level

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the proportion of respondents that trust these labels is at least 50%:  

Null hypothesis:p\geq 0.5  

Alternative hypothesis:p < 0.5  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.498 -0.5}{\sqrt{\frac{0.5(1-0.5)}{1000}}}=-0.126  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level is not provided but we can assume it as \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

So the p value obtained was a very high value and using the significance level assumed \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of respondents that trust these labels is not significanlty less than 0.5 or 50%.  

7 0
3 years ago
What minus 10 is equal to 296?​
Varvara68 [4.7K]

Answer:

306

Step-by-step explanation:

306 - 10 = 296

5 0
2 years ago
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