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erastova [34]
3 years ago
10

How to combine like terms

Mathematics
2 answers:
Mnenie [13.5K]3 years ago
8 0
1) 4x + 12x² + 9 + 3y + 2x + 11y
6x + 12x² + 14y + 9

2) x² + 2y + 15x² + 4x + 21
4x + 16x² + 2y + 21

3) 8x + 12 + 17y + 3x + y + 8
11x + 18y + 20

Hope this helps :)
dalvyx [7]3 years ago
5 0
First combine the terms with the same variable and add the coefficients. since you are working with exponents, you have to remember that the you can only combine variables with the same degree ie.
2 {x}^{2}  + 2x {}^{2}  = 4x {}^{2}
not
2 {x}^{2}  + 2 {x}^{2}  = 2x {}^{4}
now that you know this, also rememer to keep the term with the highest degree first.

so if the question is:
4x + 12x {}^{2}  + 9 + 3y + 2x + 11y
first I would combine it to

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a baseball player gets a hit 40% of the time if the weather is good but only 20% off the time if it is not good weather. The wea
rosijanka [135]

Answer: The probability of the player getting a hit is 0.214.

Step-by-step explanation:

Since we have given that

Probability  that a baseball player gets a hit if the weather is good = 40% = 0.4

Probability that a baseball player gets a hit if the weather is not good = 20% = 0.2

Probability of good weather = 7% = 0.07

Probability of not good weather = 100-7 = 93% = 0.93

According to question, the probability of the player getting hit is given by

0.4\times 0.07+0.2\times 0.93\\\\=0.214

Hence, the probability of the player getting a hit is 0.214.

8 0
3 years ago
I REALLY NEED HELP IN THIS
SVEN [57.7K]

Answer:

150°

Step-by-step explanation:

We know each angle in a equilateral triangle is 60° and that of a rectangle is 90° . So ,

\implies \angle ABC = \angle DBC + \angle ABD \\\\\implies \angle ABC = 90^o + 60^o \\\\\implies \boxed{\boxed{ \angle ABC = 150^o }}

7 0
3 years ago
Please help<br><br> Be sure to show your work and solve for f:<br> 8 = f (13-2)
Aleonysh [2.5K]

Answer:

8 = f (13-2)

8=13f-2f

8=11f

8 / 11 = 11f / 11

8/11=f

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
I need help with this
igor_vitrenko [27]

Answer:

see below

Step-by-step explanation:

Part A

Angles 1 and 5 are alternate angles (z angles), which means they are equal.

Similarly, angles 3 and 6 are alternate (z angle), which means they are equal.

Part B

Angles on a straight line add up to 180°.

8 0
2 years ago
The speed with which utility companies can resolve problems is very important. GTC, the Georgetown Telephone Company, reports it
brilliants [131]

Answer:

(a) 11.25 and 1.68  

(b) 0.1651

(c) 0.3903

(d) 0.6865

Step-by-step explanation:

We are given that GTC, the Georgetown Telephone Company, reports it can resolve customer problems the same day they are reported in 75% of the cases and suppose the 15 cases reported today are representative of all complaints.

This situation can be represented through Binomial distribution as;

P(X=r)= \binom{n}{r}p^{r}(1-p)^{n-r} ; x = 0,1,2,3,....

where,  n = number of trials (samples) taken = 15

             r = number of success

             p = probability of success which in our question is % of cases in

                  which customer problems are resolved on the same day, i.e.;75%

So, here X ~ Binom(n=15,p=0.75)

(a) Expected number of problems to be resolved today = E(X)

            E(X) = \mu = n * p = 15 * 0.75 = 11.25

    Standard deviation = \sigma = \sqrt{n*p*(1-p)} = \sqrt{15*0.75*(1-0.75)} = 1.68

(b) Probability that 10 of the problems can be resolved today = P(X = 10)

     P(X = 10) = \binom{15}{10}0.75^{10}(1-0.75)^{15-10}

                    = 3003*0.75^{10} *0.25^{5} = 0.1651

(c) Probability that 10 or 11 of the problems can be resolved today is given by = P(X = 10) + P(X = 11)

    = \binom{15}{10}0.75^{10}(1-0.75)^{15-10}+\binom{15}{11}0.75^{11}(1-0.75)^{15-11}

    = 3003*0.75^{10} *0.25^{5} + 1365*0.75^{11} *0.25^{4} = 0.3903

(d) Probability that more than 10 of the problems can be resolved today is

    given by = P(X > 10)

P(X > 10) = P(X = 11) + P(X = 12) + P(X = 13) + P(X = 14) + P(X = 15)  

= \binom{15}{11}0.75^{11}(1-0.75)^{15-11}+\binom{15}{12}0.75^{12}(1-0.75)^{15-12} + \binom{15}{13}0.75^{13}(1-0.75)^{15-13}+\binom{15}{14}0.75^{14}(1-0.75)^{15-14} + \binom{15}{15}0.75^{15}(1-0.75)^{15-15}

= 1365*0.75^{11} *0.25^{4} + 455*0.75^{12} *0.25^{3}+105*0.75^{13} *0.25^{2} + 15*0.75^{14} *0.25^{1}+1*0.75^{15} *0.25^{0}

= 0.6865

3 0
3 years ago
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