Answer:
Step-by-step explanation:
Given
Required
The product
The product is:
'
Cancel out the negative signs
Simplify fractions
By using parallel lines and transversal lines concept we can prove m∠1=m∠5.
Given that, a║b and both the lines are intersected by transversal t.
We need to prove that m∠1=m∠5.
<h3>What is a transversal?</h3>
In geometry, a transversal is a line that passes through two lines in the same plane at two distinct points.
m∠1+m∠3= 180° (Linear Pair Theorem)
m∠5+m∠6=180° (Linear Pair Theorem)
m∠1+m∠3=m∠5+m∠6
m∠3=m∠6
m∠1=m∠5 (Subtraction Property of Equality)
Hence, proved. By using parallel lines and transversal lines concept we can prove m∠1=m∠5.
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Answer:
Step-by-step explanation:
Start with our equation:
s=2(lw+wh+hl)
Plug in our values for l, w, and h:
s=2(12*9+9*2+2*12)
Simplify:
s=300
Answer:
Solving the system of equations:
x: 1
y: 2
Step-by-step explanation:
Plug it in to see if it is right, to make sure of course. Better to be safe than sorry.
Answer:
Step-by-step explanation:
1) The center lies on the vertical line x = -5 and the the circle is tangent to (touches in one place only) the y-axis. Thus, the radius is 5.
2) Starting with (x - h)^2 + (y - k)^2 = r^2 and comparing this to the given
(x - 4)^2 + (y + 3)^2 = 6^2
we see that h = 4, k = -3 and r = 6. The center is at (4, -3) and the radius is 6.
3) Notice that A and B have the same x-coordinate, x = 15. The center of the circle is thus (15, -2), where that -2 is the halfway point between the two given points in the vertical direction. Arbitrarily choose A(15, 4) as one point on the circle. Then the equation of this circle is
(x - 4)^2 + (y + 3)^2 = r^2 = 6^2, where the 6 is one half of the vertical distance between A(15, 4) and B(15, -8) (which is 12).
