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4 years ago

The ___ numbers equals the _ of ____ electrons

Physics

1 answer:

suter [353]4 years ago

8 0

The atomic number equals the number of protons and electrons (in a neutral atom)

Explanation:

An atom is composed of three types of particles:

Protons: they are found in the nucleus of the atom. They are positively charged ( $q=+1.6\cdot 10^{-19}C$ ) and have a mass of approximately $m=1.67\cdot 10^{-27}kg$
Neutrons: they are also found in the nucleus. They have no electric charge and have a mass slightly larger than that of protons
Electrons: they orbit around the nucleus. They have negative electric charge ( $q=-1.6\cdot 10^{-19}C$ ) and are much lighter than protons, having a mass of $m=9.11\cdot 10^{-31} kg$ .

An atom is also identified by two numbers:

Atomic number (Z): it is equal to the number of protons in the nucleus
Mass number (A): it is equal to the number of protons+neutrons in the nucleus

For a neutral atom, the net electric charge is zero: this means that the number of protons equals the number of electrons. But since the number of protons corresponds to the atomic number Z, this means that the atomic number is also equal to the number of electrons, for a neutral atom.

Learn more about atoms:

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Force can be represented by

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Change in momentum over time.

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3 years ago

Indigenous people sometimes cook in watertight baskets by placing hot rocks into water to bring it to a boil. What mass of 500ºC

scoray [572]

Answer:

m = 4.65 kg

Explanation:

As we know that the mass of the water that evaporated out is given as

$m = 0.0250 kg$

so the energy released in form of vapor is given as

$Q = mL$

$Q = (0.0250)(2.25 \times 10^6)$

$Q = 56511 J$

now the heat required by remaining water to bring it from 15 degree to 100 degree

$Q_2 = ms\Delta T$

$Q_2 = (4 - 0.025)(4186)(100 - 15)$

$Q_2 = 1.41\times 10^6J$

total heat required for above conversion

$Q = 56511 + 1.41 \times 10^6 = 1.47 \times 10^6 J$

now by heat energy balance

heat given by granite = heat absorbed by water

$m(790)(500 - 100) = 1.47 \times 10^6$

$m = 4.65 kg$

4 0

4 years ago

Two coils are wound around the same cylindrical form. When the current in the first coil is decreasing at a rate of -0.245 A/s ,

Airida [17]

Answer:

Complete question:

c.If the current in the second coil increases at a rate of 0.365 A/s , what is the magnitude of the induced emf in the first coil?

a. $M= 6.53\times10^{-3} H$

b.flux through each turn = Ф = $4.08\times10^{-4} Wb$

c.magnitude of the induced emf in the first coil = e= $2.38\times10^{-3} V$

Explanation:

a. rate of current changing = $\frac{di}{dt}=[tex]M=\frac{1.60\times10^{-3} V}{0.240\frac{A}{s} }}$ [/tex]

Induced emf in the coil =e= $1.60\times10^{-3} V$

For mutual inductance in which change in flux in one coil induces emf in the second coil given by the farmula based on farady law

$e=-M\frac{di}{dt}$

$M=\frac{e}{\frac{di}{dt} }$

$M=\frac{1.60\times10^{-3} }{-0.245}$

$M= 6.53\times10^{-3} H$

Flux through each turn=?

Current in the first coil =1.25 A

Number of turns = 20

using MI = NФ

flux through each turn = Ф = $\frac{6.53\times10^{-3}\times1.25}{20}$

flux through each turn = Ф = $4.08\times10^{-4} Wb$

second coil increase at a rate = 0.365 A/s

magnitude of the induced emf in the first coil =?

using $e=-M\frac{di_{2} }{dt}$

$e= 6.53\times10^{-3} \times 0.365$

magnitude of the induced emf in the first coil = e= $2.38\times10^{-3} V$

4 0

3 years ago

Calculate the ratio of the drag force on a jet flying at 1190 km/h at an altitude of 7.5 km to the drag force on a prop-driven t

Bond [772]

Answer:

$\frac{D_{jet}}{D_{prop}}=2.865$

Explanation:

Given data

Speed of jet Vjet=1190 km/h

Speed of prop driven Vprop=595 km/h

Height of jet 7.5 km

Height of prop driven transport 3.8 km

Density of Air at height 10 km p7.8=0.53 kg/m³

Density of air at height 3.8 km p3.8=0.74 kg/m³

The drag force is given by:

$D=\frac{1}{2}CpAv^2\\$

The ratio between the drag force on the jet to the drag force on prop-driven transport is then given by:

$\frac{D_{jet}}{D_{prop}}=\frac{(1/2)Cp_{7.5}Av_{jet}^2}{1/2)Cp_{3.8}Av_{prop}^2} \\\frac{D_{jet}}{D_{prop}}=\frac{p_{7.5}v_{jet}^2}{p_{3.8}v_{prop}}\\\frac{D_{jet}}{D_{prop}}=\frac{(0.53)(1190)^2}{(0.74)(595)^2}\\ \frac{D_{jet}}{D_{prop}}=2.865$

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3 years ago

A sample of a substance has a high density, yet a low particle motion. This sample must be a

avanturin [10]

The most possible answer is letter B) Liquid.
If we are going to base the answer to the motion of particles, liquid is the best answer since solid's particle cannot move for they are tightly packed while the particles of gas and plasma (ionized gas) are free and move at high speeds.

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3 years ago

Read 2 more answers

The _____ numbers equals the _____ of ______ electrons

The ___ numbers equals the _ of ____ electrons