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kenny6666 [7]
3 years ago
9

A plane is traveling at a velocity of 90 m/s. It accelerates at a constant rate of 1.5 m/s​2 until its velocity reaches 500 m/s.

What distance did the plane cover while it was accelerating?
Physics
1 answer:
katrin2010 [14]3 years ago
5 0

Answer:

The distance the plane covered while it was accelerating is 80,633.3 m

Explanation:

Given;

initial velocity of the plane, u = 90 m/s

acceleration of the plane, a = 1.5 m/s²

final velocity of the plane, v = 500 m/s

The distance covered by the plane is given as;

v² = u² + 2ad

where;

d is the distance covered by the plane;

500² = 90² + 2(1.5)d

500²  - 90² = 3d

241900 = 3d

d = 241900 / 3

d = 80,633.3 m

Therefore, the distance the plane covered while it was accelerating is 80,633.3 m

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