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inn [45]
4 years ago
7

In modern quantum–based atomic theory, what do we call the particular space around the nucleus in which an electron moves?

Physics
1 answer:
faust18 [17]4 years ago
8 0
electron cloud hope this helps
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You roll a toy car, and it moves 10 meters in five seconds. What is the car's velocity?
maks197457 [2]
  • Displacement = 10 m
  • Time = 5 s
  • We know,
  • velocity \:  \:  =  \frac{displacement}{time}  \\
  • Therefore, the car's velocity
  • =  \frac{10}{5} m/s \\  = 2m/s
<h3>Answer:</h3>

The car's velocity is 2 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

8 0
2 years ago
A uniform beam is suspended horizontally by two identical vertical springs that are attached between the ceiling and each end of
puteri [66]

The frequency and amplitude of the SHM beam is 0.8 Hz and 0.098 m. The frequency of the SHM wave when gravel falls is 0.8 Hz and the amplitude of subsequent SHM beam is 0.4m.

(a) Mass of the spring = 225 Kg

Mass of the sack = 175 Kg

Amplitude of the beam = 40 cm = 0.40 m

Frequency of the beam = F = 0.60 cycles/s

The formula for frequency of oscillation =

= f = (1/2π) X √(k/m)

where, k = 2π²F²m

= k = 2 X (3.14)² X 0.6² X (225 + 175)

= k = 5685.37 N/m

Strength of the spring before gravels fall = x =

= x = mg / k

= x = [ (225 + 175 ) X 9.8 ] / 5685.37

= x = 0.689 m

But, the spring is stretched by the distance of x' which is expressed as,

= X = x - x'

= X = 0.689 - 0.40

= X = 0.289 m

Now, since we know that the gravel falls, thus frequency = f =

= f = (1/2π) X √(k/m)

= f= (1/ 2 X 3.14) X √ 5685.37 / 225

= f = 0.8 Hz

(b) Assuming that the spring is stretched, x = mg/k =

= x = (225 X 9.8) / 5685.37

= x = 0.3878 m

Thus, the amplitude of the sack = A = 0.3878 - 0.289

= A = 0.098 m

(c) If the gravel falls, the speed is maximum hence speed = s =

= s = A X √(k/m)

= s = 0.4 X √(5685.37/400)

= s = 1.508 m/s

The frequency = f' =

= f' = (1/2π) X √(k/m)

= f' = (1/2 X 2.14) X √(5685.37/225)

= f' = 0.8 Hz

(d) New amplitude = A' =

= A' = 0.38 + 0.038   (after calculating the new distance)

= A' = 0.4 m

To know more about Spring:

brainly.com/question/15850235

#SPJ4

8 0
2 years ago
The mass of a moving object increases, but its speed stays the same. What happens to the kinetic energy of the object as a resul
Ronch [10]

Answer:

kinetic energy increases because of speed and motion overall

Explanation:

dont know if i helped you but you can give me a thumbs down if you hate the answer or it is not the answer you are looking for

8 0
3 years ago
If you push a box across the floor, the box experiences what kind of friction?
Talja [164]
I think it is kinetic friction not the best at physics
4 0
3 years ago
Read 2 more answers
John, paul, and george are standing in a strawberry field. paul is 14.0 m due west of john. george is 36.0 m from paul, in a dir
sdas [7]

Position of paul with respect to john is given as

14 m due west of john

r_{pj} = r_p - r_j = -14\hat i

position of George with respect to Paul is given as 36 m in direction 37 degree south of east

r_{GP} = r_G - r_p = 36cos37\hat i - 36 sin37\hat j

now we need to find the position of George with respect to John

r_{GJ} = r_G - r_j[\tex]now for the above equation we can add the two equations[tex]r_{Gj} = -14\hat i + 36 cos37\hat i - 36sin37\hat j

r_{Gj} = 14.75\hat i - 21.67\hat j

so the magnitude is given as

r = \sqrt{14.75^2 + 21.67^2} = 26.2 m

and direction is given as

\theta = tan^{-1}\frac{21.67}{14.75}= 55.75 degree

<em>so it is 26.2 m at an angle 55.75 degree South of east</em>

7 0
3 years ago
Read 2 more answers
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