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4 years ago

PLZ HELP !!

Mathematics

1 answer:

sdas [7]4 years ago

4 0

Answer:

The final balance is $1,692.94.

The total compound interest is $392.94.

Step-by-step explanation:

1,300 x 0.045=___ x 6

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Find the difference quotient f(x)=2x^2+5x

expeople1 [14]

Step-by-step explanation:

Step 1: Find the difference quotient

$f(x+h) = 2(x+h)^2 + 5(x+h)$

$f(x+h) = 2(x^2+2xh+h^2)+5x+5h$

$f(x+h) = 2x^2+4xh+2h^2+5x + 5h$

$f(x) = 2x^2 + 5x$

Plug it into the formula

Difference Quotient: $\frac{f(x+h)-f(x)}{h}$

$\frac{2x^2+4xh+2h^2+5x+5h - (2x^2+5x)}{h}$

$\frac{2x^2 - 2x^2 + 4xh + 2h^2 + 5x - 5x + 5h}{h}$

$\frac{2h^2+4xh+5h}{h}$

Pull out an h

$\frac{h(2h+4x+5)}{h}$

$2h+4x+5$

Answer: $2h+4x+5$

6 0

3 years ago

Read 2 more answers

The cartesian coordinates of a point are given. find polar coordinares of the point where r<0 and

Ad libitum [116K]

Find the polar coordinates in the usual way, then negate r and add 180° to θ.

You know that

... r = √(x² + y²)

... θ = arctan(y/x) . . . . . taking quadrant into account

The coordinates (r, θ) and (-r, θ+180°) specify the same point.

8 0

3 years ago

A random sample of 28 statistics tutorials was selected from the past 5 years and the percentage of students absent from each on

SVEN [57.7K]

Answer:

Step-by-step explanation:

Hello!

X: number of absences per tutorial per student over the past 5 years(percentage)

X≈N(μ;σ²)

You have to construct a 90% to estimate the population mean of the percentage of absences per tutorial of the students over the past 5 years.

The formula for the CI is:

X[bar] ± $Z_{1-\alpha /2}$ * $\frac{S}{\sqrt{n} }$

⇒ The population standard deviation is unknown and since the distribution is approximate, I'll use the estimation of the standard deviation in place of the population parameter.

Number of Absences 13.9 16.4 12.3 13.2 8.4 4.4 10.3 8.8 4.8 10.9 15.9 9.7 4.5 11.5 5.7 10.8 9.7 8.2 10.3 12.2 10.6 16.2 15.2 1.7 11.7 11.9 10.0 12.4

X[bar]= 10.41

S= 3.71

$Z_{1-\alpha /2}= Z_{0.95}= 1.645$

[10.41±1.645* $(\frac{3.71}{\sqrt{28} } )$ ]

[9.26; 11.56]

Using a confidence level of 90% you'd expect that the interval [9.26; 11.56]% contains the value of the population mean of the percentage of absences per tutorial of the students over the past 5 years.

I hope this helps!

7 0

4 years ago

PLEASE MAKE SURE HELP MEEEEEEEEE!

Tanzania [10]

Yes it’s correct :))))

6 0

3 years ago

Read 2 more answers

Help me plz....................

nataly862011 [7]

Answer: