Answer:
It's heavy cream
Step-by-step explanation:
Homogenized milk has a density of 1.032 kg/L and
heavy cream has a density of 1.005 kg/L at 10°C.
At 10°C, a container holding 8 liters of liquid weighs 8.04 kilograms
To determine which container hold homogenized milk or heavy cream and How I know?
We findo the density of the measurements given and whatever it correspond to is what it is
First mass is 8.04kg
Liquid contained is 8 litres
SInce the density is kg/L
No need for conversion
Density = mass/volume = 8.04/8= 1.005kg/L
Heavy cream has a density of 1.005 kg/L at 10°C.
Therefore it correspond
Circumference is Diameter * 3.14
so D * 3.14 = 31.4
31.4 / 3.14 = 10 so the diameter is 10.
the radius is half of the diameter so radius = 5 centimeters.
Answer:
k = - 
, k = 2
Step-by-step explanation:
Using the discriminant Δ = b² - 4ac
The condition for equal roots is b² - 4ac = 0
Given
kx² + 2x + k = - kx ( add kx to both sides )
kx² + 2x + kx + k = 0 , that is
kx² + (2 + k)x + k = 0 ← in standard form
with a = k, b = 2 + k and c = k , thus
(2 + k)² - 4k² = 0 ← expand and simplify left side
4 + 4k + k² - 4k² = 0
- 3k² + 4k + 4 = 0 ( multiply through by - 1 )
3k² - 4k - 4 = 0 ← in standard form
(3k + 2)(k - 2) = 0 ← in factored form
Equate each factor to zero and solve for k
3k + 2 = 0 ⇒ 3k = - 2 ⇒ k = -
k - 2 = 0 ⇒ k = 2
Answer:
I cant see good
Step-by-step explanation:
To figure that out you could do 99 minus 38, which would lead you to your answer 61.
