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10th
Maths
Pair of Linear Equations in Two Variables
Algebraic Solution of a Pair of Linear Equations
Solve: 3x + 4y = 10,2x - 2y...
MATHS
Asked on December 27, 2019 byShweta Rudravaram
Solve: 3x+4y=10,2x−2y=2 by the method of elimination.
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ANSWER
3x+4y=10 …………..(1)
2x−2y=2 (or) x−y=1 …………(2)
(1) ⇒(3x+4y=10)1
(2) ⇒(x−y=1)3
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3x+4y=10
3x−3y=3
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7y=7
∴y=1
Put y=1 in (1) we get 3x+4×1=10
3x=10−4=6
∴x=36=2
Hence x=2,y=1.
Answer:
b. Kathy
Step-by-step explanation:
We compare each of their score by how far away from the mean when in term of the standard deviation. Using the following formula
For John he is (85 - 75)/5 = 2.
For Kathy she is (80 - 50)/10 = 3.
Since Kathy is 3 standard deviation better than her class' average, while John is only 2's. We conclude that Kathy did better.
Answer:
4 hours
Step-by-step explanation:
1+1=2
6-2=4
Remark
It is not a straight line distance from the park to the mall. None of the answers give you that result. And if you know what displacement is, none of the answers are really displacement either. The distance is sort of a "as the crow flies." distance. There's a stop off in the middle of town.
Method
You need to use the Pythagorean Formula twice -- once from the park to the city Center and once from the city center to the mall.
Distance from the Park to the city center.
a = 3 [distance east]
b = 4 [distance south]
c = ??
c^2 = 3^2 + 4^2 Take the square root of both sides.
c = sqrt(3^2 + 4^2)
c = sqrt(9 + 16) Add
c = sqrt(25)
c = 5
So the distance from the park to the city center is 5 miles
Distance from City center to the mall
a = 2 miles [distance east]
b = 2 miles [distance north]
c = ??
c^2 = a^2 + b^2 Substitute
c^2 = 2^2 + 2^2 Expand this.
c^2 = 4 + 4
c^2 = 8 Take the square root of both sides.
sqrt(c^2) = sqrt(8)
c = sqrt(8) This is the result
c = 2.8
Answer
Total distance = 5 + 2.8 = 7.8
Answer:
1 and 3, 2 and 4, 5 and 7, and 8 and 65
Step-by-step explanation:
Vertical Angles Congruence Theorem
