Answer:
I believe your answer is A.
Step-by-step explanation:
2x2x2
2x2=4
4x2=8
Therefore, x=2.
Answer:
1. 6/10 – 2/5 =
Ans: 2/10, which can be reduced to 1/5.
2. If a tank is 5/8 filled with solution, how much of the tank is empty?
Ans: 3/8 of the tank is empty. Since the whole tank would equal 8/8, or 1, and 5/8 of it is filled, then that
means 3/8 of it remains empty.
3. 1/2 x 3/5 x2/3 =
Ans: 6/30, which can be reduced to 1/5.
4. 5/9 ÷ 4/11 =
Ans: 55/36. You cannot reduce this fraction any further.
5. Convert 27/4 to a decimal.
Ans: 6.75. This answer is arrived at by dividing 4 into 27.
6. Convert 0.45 to a fraction.
Ans: 45/100, which can be reduced to 9/20.
7. 4.27 x 1.6 =
Ans: 6.832
8. 6.5 ÷ 0.8 =
Ans: 8.125
9. 12 + 4.52 + 245.621 =
Ans: 262.141
Step-by-step explanation:
Answer:
Hello! After reading your question I have deduced that the correct answer is 288² cm.
Step-by-step explanation:
The way I came to this conclusion was as follows:
Firstly:
If said rectangle is two squares put side by side (adjacent), then a valid assumption is that both squares are the same size.
This is because all four sides of a square have to be equal.
Thus if the two squares are joined together on one side, then all the other sides of both the squares will be the same length.
Thus both of the squares are going to be the same size, so they will have the same area.
Secondly:
If the area of one square is 144² cm then the area of the other square should also be 144² cm.
Thus if you combine the areas of both the squares, that make up the rectangle, you are left with the area of the rectangle being 288² cm.
I hope this helped!
Answer:
<h2>x = 28</h2>
Step-by-step explanation:
ΔARP and ΔCRD are similar. Therefore the sides are in proportion:
We have:
AR = 10 + x
CR = x
PR = 15 + 42 = 57
DR = 42
Substitute:
<em>cross multiply</em>
<em>use distributive property</em>
<em>subtract 42x from both sides</em>
<em>divide both sides by 15</em>
Answer:
A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers is a(n) __uniform__________ distribution
Step-by-step explanation:
Given that there is a continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers
Since the pdf is rectangular in shape and total probability is one we can say all values in the interval would be equally likely
Say if the interval is (a,b) P(X) = p the same for all places
Since total probability is 1,
we get integral of P(X)=p(b-a) =1
Or p=
this is nothing but a uniform distribution continuous defined in the interval
A continuous probability distribution having a rectangular shape, where the probability is evenly distributed over an interval of numbers is a(n) __uniform__________ distribution