Well you have cut it into smaller pieces so it would be I guess 4 grams now because 20 divided by 5 is 4.
Answer:
44
Step-by-step explanation:
if she had 10 left at the end and you add the other half from lunch which is 12, then that gives you 22. Since before lunch she had half (22), all you gotta do is add the other half which is 22. 22+22=44 and that's your answer.
We know that the amounts earned by Dawn, Doug and Dale are from the list of numbers: $9.35, $8.52 and $8.25
We also know that Dale and Doug earned close to $9.00
And that Dawn earned $1.10 less than Dale
Let the amount earned by Dale be x
⇒ Amount earned by Dawn is x - 1.1
If we notice the list of numbers, we see that $9.35 and $8.25 differ by $1.1
Hence, Dale earned $9.35 and Dawn earned $8.25
We are now left with $8.52, which should be the amount earned by Doug. This is correct, since we also know that Doug earned close to $9.
Hence, the amounts earned are:
Dale: $9.35
Doug: $8.52
Dawn: $8.25
Answer:
(3x+4)(5x+7)
Step-by-step explanation:
15x^2
+41x+28
Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2
+ax+bx+28. To find a and b, set up a system to be solved.
a+b=41
ab=15×28=420
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.
1,420
2,210
3,140
4,105
5,84
6,70
7,60
10,42
12,35
14,30
15,28
20,21
Calculate the sum for each pair.
1+420=421
2+210=212
3+140=143
4+105=109
5+84=89
6+70=76
7+60=67
10+42=52
12+35=47
14+30=44
15+28=43
20+21=41
The solution is the pair that gives sum 41.
a=20
b=21
Rewrite 15x^2
+41x+28 as (15x^2
+20x)+(21x+28).
(15x^2
+20x)+(21x+28)
Factor out 5x in the first and 7 in the second group.
5x(3x+4)+7(3x+4)
Factor out common term 3x+4 by using distributive property.
(3x+4)(5x+7)
