Ughhh...the limit formula...this should be thrown in the trash the minute you start doing derivatives :P
(-8-9(t+d)-(-8-9t))/(t+d-t)
(-8-9t-9d+8+9t)/d
-9d/d (which is -9 for any value of d as well as when d approaches zero)
-9
So the instantaneous velocity is regardless of t or delta t
Answer:
-19 ½
Step-by-step explanation:
6 × -3 = -18
½ × -3 = -1 ½
-18 + -1 ½ = -19 ½
Answer:
AE = 15 cm; ED = 18 cm; AD = 15 cm (given)
Step-by-step explanation:
ΔBEC ~ ΔAED so ...
AD/BC = AE/BE = (BE+AB)/BE = 1 + AB/BE
Substituting given numbers (lengths in centimeters), we have ...
15/10 = 1 + 5/BE
1/2 = 5/BE
BE = 10
Similarly, ...
1/2 = 6/CE
CE = 12
Then the unknown sides are ...
AE = AB + BE = 5 + 10 = 15 . . . cm
ED = CE + CD = 12 + 6 = 18 . . . cm
Answer:
B, 10
Step-by-step explanation:
W/36=5/18
W/36=5/18 cress cross
18w=5x36
18w=180
18w/18=180/18
W=10