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QveST [7]
3 years ago
5

A relation of the graphed below is NOT considered a function because of which pair of coordinates:

Mathematics
1 answer:
motikmotik3 years ago
8 0
I think the answer is (-2,-1). 
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Point X has coordinates (-4, -5) and point y has coordinates (--1, --5 ) which expression models the distance between points X a
sdas [7]

Answer:  The last expression shows the result of 3  so it models the distance between x and y.

Step-by-step explanation:

First you will have to  find the distance between the two points by square the x coordinates and squaring the y coordinates to find their sum .  

-4 - (-1) = -3

-5 - ( -5) = 0

-3^2 + 0^2 = d^2   where d  is the distance

9  = d^2

d= 3  

The distance is 3 units  

Now evaluate which expression have a solution as 3.

The last expression is the answer

the absolute value for -4 is 4   , and the absolute value for -1 is 1  and 4 minus 1 is 3.

4 0
3 years ago
When a number x is multiplied by 4 the result is 2/5 what is the vaule of x
topjm [15]
2/5 as a decimal is 0.4 
4*0.1=0.4 
meaning x is 0.1
7 0
3 years ago
Read 2 more answers
THIS IS TIMED!<br><br> Thanks:)
VLD [36.1K]
Here see the attachment....:)

7 0
3 years ago
What is the radius of a circle with a circumference measuring 24 pie cm?
Tpy6a [65]
By the way, it's pi, not pie. just wanted you to know as you may lose marks in tests for spelling (but i may be wrong)

we know circumference is pi multiplied by the diameter.
the diameter is 2x the radius
we can re-arrange the first fact to get:
diameter (or 2x radius) = circumference divided by pi.
since the circumference is 24pi we can cancel off pi from the circumference (24pi) and pi.
now we have the diameter = 24
since the diameter is 2x the radius you divide both sides by 2 and get:
radius=12cm
5 0
3 years ago
What is the factored form of the expression?<br><br> d^2 = 36d + 324
Veseljchak [2.6K]

Answer:

(x-43.45)(x+7.45)=0

Step-by-step explanation:

We have the quadratic equation d^{2}=36d+324  i.e. d^{2}-36d-324=0

As, the roots of the quadratic equation ax^{2}+bx+c=0 are given by x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}.

So, from the given equation, we have,

a = 1, b = -36 , c = -324.

Substituting the values in x=\frac{-b\pm \sqrt{b^{2}-4ac}}{2a}, we get,

x=\frac{36\pm \sqrt{(-36)^{2}-4\times 1\times (-324)}}{2\times 1}

i.e. x=\frac{36\pm \sqrt{1296+1296}}{2}

i.e. x=\frac{36\pm \sqrt{2592}}{2}

i.e. x=\frac{36\pm 50.9}{2}

i.e. x=\frac{36+50.9}{2}  and x=\frac{36-50.9}{2}

i.e. x=\frac{86.9}{2}  and x=\frac{-14.9}{2}

i.e. x = 43.45 and x = -7.45

Thus, the roots of the equation are 43.45 and -7.45.

Hence, the factored form of the given expression will be (x-43.45)(x+7.45)=0

3 0
3 years ago
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