Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The
1 answer:
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Answer:
Quadratic formula is in the 2nd picture.
Step-by-step explanation:
Answers in the photo.
Solve the equation for r by finding a,b, and c of the quadratic then applying the quadratic formula.
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Answer:
- parallel: y = 4x -6
- perpendicular: y = -1/4x +27/4
Step-by-step explanation:
If we want the new line to be written in slope-intercept form, we need to find the new value of the y-intercept. The equation of the line is ...
y = mx +b . . . . . . . for slope m and y-intercept b
Solving for b gives ...
b = y -mx . . . . . . . subtract mx from both sides.
The values of x and y come from the point we want the line to pass through. The value of m will be the same for the parallel line as for the given line: 4. For the perpendicular line, it will be the opposite reciprocal of this: -1/4.
<u>Parallel line</u>
b = 6 -4(3) = 6 -12 = -6
y = 4x -6
Perpendicular line
b = 6 -(-1/4)(3) = 6 +3/4 = 27/4
y = -1/4x +27/4
Answer:
is the equation of line in slope intercept form.
Step-by-step explanation:
Line runs through points begin ordered pair negative 3 comma 0 end ordered pair and begin ordered pair 0 comma 4.
First ordered pair: (-3,0)
Second ordered pair: (0,4)
We have two points and need to find equation of line in slope intercept form
y-intercept, when x=0 , (0,4)
Equation of line in slope intercept form:
y=mx+b
where, and b=4
Required equation:
Thus, is the equation of line in slope intercept form.