Answer:
Step-by-step explanation:
Begin by dividing by 5
2x + 4 = 3
Is this written as 2^(x + 4) = 3? I think it is.
Take the log of both sides
log 2^(x + 4) = log(3)
(x + 4) * log(2) = log 3
log 2 = 0.30103
log 3 = 0.47712
(x + 4) = log2 / log3
x + 4 = 0.63093 Add 4 to both sides
x = -3.369 Rounded to the nearest thousandth
====================
If you mean the question exactly as it is written (the 4 is not part of the power)
5(2^x + 4) = 15
2^x + 4 = 3
2^x = 3 - 4
2^x = - 1
This can't be done 2 to any power should be >0.
if x>0 then this will give an ever increasing number
if xK0 then this will give an ever decreasing answer but still greater than 0.
No value will make 2^x go to something minus.
If I have misread this in some way, leave a note and I will get back to you.
Answer:
(-2, 20)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
- Coordinates (x, y)
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y = -7x + 6
y = -10x
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitute in <em>y</em> [1st Equation]: -10x = -7x + 6
- [Addition Property of Equality] Add 7x on both sides: -3x = 6
- [Division Property of Equality] Divide -3 on both sides: x = -2
<u>Step 3: Solve for </u><em><u>y</u></em>
- Substitute in <em>x </em>[2nd Equation]: y = -10(-2)
- Multiply: y = 20
Suppose

is the number of possible combinations for a suitcase with a lock consisting of

wheels. If you added one more wheel onto the lock, there would only be 9 allowed possible digits you can use for the new wheel. This means the number of possible combinations for

wheels, or

is given recursively by the formula

starting with

(because you can start the combination with any one of the ten available digits 0 through 9).
For example, if the combination for a 3-wheel lock is 282, then a 4-wheel lock can be any one of 2820, 2821, 2823, ..., 2829 (nine possibilities depending on the second-to-last digit).
By substitution, you have

This means a lock with 55 wheels will have

possible combinations (a number with 53 digits).
Answer:
Less than.
Step-by-step explanation: