1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nostrana [21]
3 years ago
12

An expression is shown below: 3pf^2 − 21p^2f + 6pf − 42p^2 Part A: Rewrite the expression by factoring out the greatest common f

actor. (4 points) Part B: Factor the entire expression completely. Show the steps of your work. (6 points)
Mathematics
1 answer:
jonny [76]3 years ago
3 0

Hey there! I'm happy to help!

<u>PART A</u>

Let's break down each terms in the expression to find the factors that make it up and see the greatest thing they all have in common

To break up the numbers, we keep on dividing it until there are only prime numbers left.

TERM #1

Three is a prime number, so there is no need to split it up.

3pf²= 3·p·f·f              

TERM #2

We have a negative coefficient here. First, let's ignore the negative sign and find all of the factors, which are just 7 and 3. One of them has to be negative and one has to be positive for it to be negative. It could be either way, and when comparing to other, we might want one to be negative or positive to match another part of the expression to find the greatest common factor. So, we will use the plus or minus sign ±, knowing that one must be positive and one must be negative.

-21p²2f= ±7·±3 (must be opposite operations) ·p·p·f

TERM #3

6pf= 2·3·p·f

TERM #4

Since 42 is made up of 3 prime factors (2,3,7), one of them or all three must be negative, because two negatives would make it positive. We will use the plus-minus sign again on all three because it could be just one is negative or all three are, but we don't know. We can use these later to find the greatest common factor when matching.

-42p²= ±2·±3·±7·p·p

Now, let's pull out all of our factors and see the greatest thing all four terms have in common

TERM 1: 3·p·f·f  

TERM 2: ±7·±3·p·p·f     (7 and 3 must end up opposite signs)

TERM 3: 2·3·p·f

TERM 4: ±2·±3·±7·p·p   (one or three of the coefficients will be negative)

Let's first look at the numbers they share. All of them have a three. We will rewrite Term 2 as -7·3·p·p·f afterwards because 3 must be positive to match. With term four, the 3 has to positive so not all three can be negative, so that means that either the 2 or 7 has to be negative, but in the end we they will make a -14 so it does not matter which one because.

Now, with variables. All of them have one p, so we will keep this.

Almost all had an f except the fourth, so this cannot be part of the GCF.

So, all the terms have 3p in common. Let's take the 3p out of each term and see what we have left. In term 4 we will combine our ±7 and ±2 to be -14 because one has to be negative.

TERM 1: f·f

TERM 2: -7·p·f

TERM 3: 2·f

TERM 4: -14·p

The way we will write this is we will put 3p outside parentheses and put what is left of all of our terms on the inside of the parentheses.

3p(f·f+-7·p·f+2·f-14·p)

We simplify these new terms.

3p(f²-7pf+2f-14p)

Now we combine like terms.

3p(f²-7pf-14p)

If you used the distributive property to undo the parentheses you could end up with our original expression.

<u>PART B</u>

Completely factoring means the equation is factored enough that you cannot factor anymore. The only things we have left to factor more are the terms inside the parentheses. Although there won't be something common between all of them, one might have pairs with one and not another, and this can still be factored out, and this can be put into (a+b)(a+c). Let's find what we have in common with the three terms in the parentheses.

TERM 1: f·f

TERM 2: -7·p·f

TERM 3: 2· -7·p (I just put 7 as negative and 2 as positive already for matching)

Term 1 and 2 have an f in common.

Terms 2 and 3 have a -7p in common.

So, we see that the f and the -7p are what can be factored out among all of the terms, so let's take it out of all of them and see what is left.

Term 1: f

Term 2: nothing left here

Term 3: 2

So, this means that all we have left is f+2. If we multiply that by f-7p we will have what was in the parentheses in our answer from Part A, and we cannot simplify this any further. This means that our parentheses from Part A= (f-7p)(f+2). This shows that (f-7p) is multiplied by (f+2)

Don't forget the GCF 3p; that's still outside the parentheses!

Therefore, the answer here is 3p(f-7p)(f+2).

Have a wonderful day! :D

You might be interested in
3.Solve the system of equations: X-4y=-22 x+4y=10​
laila [671]

Answer:

-0.5

Step-by-step explanation:

Use the simultaneous equations method:

x - 4y = 6

3x + 4y = 10

Add these two equations together to cancel out 'y':

4x = 16

Divide both sides by 4:

x = 4

substitute this value into one of the equations:

(4) - 4y = 6

Subtract 4 from both sides:

- 4y = 2

Divide both sides by -4:

y = -0.5

goodluck!

6 0
3 years ago
Please help me
iVinArrow [24]

Answer:

i think 4 th option

if u want to verify just substitute (4,-2)

8 0
4 years ago
What is the greatest integer n that satisfies 100^2 - n^2 = n^2 - 100^2
Anika [276]

Answer:

n = 100, -100

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Who can solve 3|2y-4|-7=17
umka21 [38]

Answer:

no, i cant solve it in paper but i can in my brain

Step-by-step explanation:

3 0
3 years ago
The Continuing Education Division at the Ozark Community College offers a total of 30 courses each semester. The courses offered
dybincka [34]

Answer:

The college should offer 20 practical courses and 10 humanistic courses in order to maximize the revenue.

Step-by-step explanation:

a)

Let x and y be  

<em>x= number of practical courses the college will offer</em>

<em>y= number of humanistic courses the college will offer</em>

we have the following inequalities

x ≥ 10

y ≥ 10

x+y = 30

The only points (x,y) that satisfy all this inequalities are (10,20) and (20,10) (see picture attached).

On the other hand, the revenues would be given by  

R = 1,500x + 1,000y

The maximum of R is attained in (x,y) = (20,10) and is  

R = 300,000 + 100,000 = 400,000

and the college should be offering 20 practical courses and 10 humanistic ones.

b)  

If x = 21 then y must be 9, and then y does not satisfy y ≥ 10.

So you can only offer additional humanistic courses.

In n is an integer < 30

But if y=10+n  then x must be 30-n and the revenue would be

R = 1,500(30-n) + 1,000(10+n) =  

350,000 - 1,500n + 100,000+ 1,000n =  

400,000 - 500n < 400,000

This result means in terms of offering additional courses, that is not worth doing it.

8 0
3 years ago
Other questions:
  • I’m pretty sure the answer is 50.3 but could someone please tell me if it’s square yards or yards?
    13·1 answer
  • Which power of 2 is equal to this expression: (2•2•2)-2
    12·2 answers
  • the height of a cylinder is 5 units less than 3 times it’s radius, which expression represents the height of the cylinder in ter
    7·1 answer
  • You burned a CD of your music and then created an artistic CD label
    9·2 answers
  • What is 21 1/2‐6 1/2​
    13·1 answer
  • How do I solve |y-9| = 6? <br> 25 POINTS!
    14·1 answer
  • Given the following system, what would be the best way to start slowing the system?
    13·1 answer
  • The value
    12·1 answer
  • I need help with this
    13·1 answer
  • Thor’s hammer can cover 4.95 km in a second. How many kilometers will it cover in 4.95 seconds
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!