The first step is to determine the zeros of p(x).
From the Remainder Theorem,
p(a) = 0 => (x-a) is a factor of p(x), and x=a is a zero of p(x).
Try x=3:
p(3) = 3^3 - 3*3^2 - 16*3 + 48 = 27 - 27 - 48 + 48 = 0
Therefore x=3 is a zero, and (x-3) is a factor of p(x).
Perform long division.
x² - 16
-------------------------------------
x-3 | x³ - 3x² - 16x + 48
x³ - 3x²
-----------------------------------
- 16x + 48
- 16x + 48
Note that x² - 6 = (x+4)(x-4).
Therefore the complete factorization of p(x) is
p(x) = (x-3)(x+4)(x-4)
To determine when p(x) is negative, we shall test between the zeros of p(x)
x p(x) Sign
---- --------- ---------
-4 0
0 48 +
3 0
3.5 -1.875 -
4 0
p(x) is negative in the interval x = (3, 4).
Answer
The time interval is Jan. 1, 2014 to Jan. 1, 2015.
Answer:
x/2x+3 + 2x +3/x = 184 /65
x(2x + 3)–1 + (2x+3)x-1 = 184/65
(2x + 3)x / (2x +3)x = 184/65
2x² + 3x / 2x² + 3x = 184/65
1x= 184/64
x = 184/64
Answer:
5 hours
Step-by-step explantioon:
35x+75=20x+150
15x+75=150
15x=75
x=5
If I did my math correctly I believe your answer will be C. :)
