HALP PLEASE NEED HALP, ASAP??

Mathematics

1 answer:

andre [41]2 years ago

7 0

Answer:

Step-by-step explanation:

since -4 *-2 = 8 and -8+8=0

0*-2=0

0+5=5

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Can someone please help me on this THIS IS URGENT!!!!

andre [41]

What are we helping with

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2 years ago

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solve the following system of equations. Enter the x-coordinate of the solution. Round answer to the nearest tenth. 5x+2y=22 -2x

melisa1 [442]

Answer:

A) 5x + 2y = 22

B) -2x + 6y = 3 We'll multiply A) by -3

A) -15x -6y = -66 Then we'll add B)

B) -2x + 6y = 3

-17x = -63

x = 3.7058823529

y = 1.7352941178

Step-by-step explanation:

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2 years ago

A kennel is moving 160 dogs to a new facility each dog has its own crate the facility manager rents 17 trucks each truck holds 9

mina [271]

This will only be able to hold 153 dogs in total. He will need 1 additional truck to hold the last 7 dogs.

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2 years ago

two cars travel at same speed to different destinations. car A reaches its destination in 24 minutes. car B reaches its destinat

Harlamova29_29 [7]

Answer:

The speeds of the cars is: 0.625 miles/minute

Step-by-step explanation:

We use systems of equations in two variables to solve this problem.

Recall that the definition of speed (v) is the quotient of the distance traveled divided the time it took : $v=\frac{distance}{time}$ . Notice as well that the speed of both cars is the same, but their times are different because they covered different distances. So if we find the distances they covered, we can easily find what their speed was.

Writing the velocity equation for car A (which reached its destination in 24 minutes) is:

$v\,*\,24\,min=d_A$

Now we write a similar equation for car B which travels 5 miles further than car A and does it in 32 minutes:

$v\,*\,32\,min=d_A+5\,miles$

Now we solve for $d_A$ in this last equation and make the substitution in the equation for car A:

$v\,*\,32\,min=d_A+5\,miles\\d_A=v\,*\,32\,min-5\,miles\\\\v\,*\,24\,min=v\,*\,32\,min-5\,miles\\v\,(24\,min-32\,min)=-5\,miles\\v\,(-8\,min)=-5\, miles\\v=\frac{-5}{-8} \frac{miles}{min} \\v=0.625\,\frac{miles}{min}$