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Mumz [18]
2 years ago
7

Find Theta in degrees. WILL MARK BRAINLIEST I PROMISE<3333

Mathematics
1 answer:
Semmy [17]2 years ago
3 0

Answer:

sin \alpha   =  \frac{opposite}{hypotenuse}  \\ sin   \alpha  =  \frac{8}{17}  \\ sin \alpha  =  0.470588235294117 \\  \alpha  =  {sin}^{ - 1} (0.470588235294117) \\  \alpha  = 28.07 \: degrees

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A furniture store received an order for 3,456 chairs. they can fit 9 chairs in a large shipping box. how many shipping boxes wil
kykrilka [37]
This is simple :)
If 9 chairs can fit in one box, and you have 3,456 chairs, just divide how many chairs you have by how many can fit in the box in order to find how many boxes you will need.

3,456/9 = 384
384 boxes will be needed
7 0
3 years ago
Drag steps of the solution into order to solve for x in the equation 6(x-5) = 54
telo118 [61]

The steps of the solution into order to solve for x in the equation 6(x-5) = 54 are:

  • A. 6x – 30 = 54
  • B. 6x = 84  
  • D. x = 14

Given the expression 6(x-5) = 54

Expand the expression in parenthesis using the distributive law;

6x - 6(5) = 54

6x - 30 = 54

Add 30 to both sides

6x - 30 + 30 = 54 + 30

6x = 84

Divide both sides by 6

6x/6 = 84/6

x = 14

Therefore the steps of the solution into order to solve for x in the equation 6(x-5) = 54 are:

  • A. 6x – 30 = 54
  • B. 6x = 84  
  • D. x = 14

Learn more on equations here; brainly.com/question/2972832

7 0
2 years ago
A random sample of 100 automobile owners in thestate of Virginia shows that an automobile is driven onaverage 23,500 kilometers
Anastaziya [24]

Answer:

a) 22497.7 < μ< 24502.3

b)  With 99% confidence the possible error will not exceed 1002.3

Step-by-step explanation:

Given that:

Mean (μ) = 23500 kilometers per year

Standard deviation (σ) = 3900 kilometers

Confidence level (c) = 99% = 0.99

number of samples (n) = 100

a) α = 1 - c = 1 - 0.99 = 0.01

\frac{\alpha }{2} =\frac{0.01}{2}=0.005\\ z_{\frac{\alpha }{2}}=z_{0.005}=2.57

Using normal distribution table, z_{0.005 is the z value of 1 - 0.005 = 0.995 of the area to the right which is 2.57.

The margin of error (e) is given as:

e= z_{0.005}\frac{\sigma}{\sqrt{n} }  = 2.57*\frac{3900}{\sqrt{100} } =1002.3

The 99% confidence interval = (μ - e, μ + e) = (23500 - 1002.3, 23500 + 1002.3) =  (22497.7, 24502.3)

Confidence interval = 22497.7 < μ< 24502.3

b) With 99% confidence the possible error will not exceed 1002.3

5 0
3 years ago
What is the equation of the line that best fits the given data?
skad [1K]
Your answer is A.) for ur problem
8 0
3 years ago
Read 2 more answers
Find the factors of 200m2 - 800n2.
leonid [27]

Answer:

Step-by-step explanation:

200m^2-800n^2=200(m^2-4n^2)

8 0
2 years ago
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