Answer:
1). m∠ACE = 115°
2). m(∠DCB) = 35°
3). m(∠ACB) = 30°
Step-by-step explanation:
In the diagram attached,
1). AB and CD are the parallel lines and the line AC is a transverse,
m(∠ABC) = 35°
m(∠BAC) = 115°
∠BAC ≅ ∠ACE [Alternate interior angles]
m(∠ACE) = m(∠BAC) = 115°
2). Since, AB and CD are the parallel lines and line CB is a transverse,
∠ABC ≅ ∠DCB [Alternate interior angles]
m(∠ABC) = m(∠DCB) = 35°
3). From ΔACB,
m(∠ACB) + m(∠CBA) + m(BAC) = 180°
m(∠ACB) + 35° + 115° = 180°
m(∠ACB) = 30°
