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vlabodo [156]
4 years ago
15

Use the periodic table to determine which of the

Chemistry
1 answer:
sveticcg [70]4 years ago
3 0

Answers :

B , C

Explanation :

[ Correct on Ed 2020 ]

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The density of benzene at 15 °c is 0.8787 g/ml. Calculate the mass of 0.1500 l of benzene at this temperature. Enter your answer
Otrada [13]

Answer:

131.8 g.

Explanation:

  • There is a relation that relates the density of the substance (d) to the mass (m) and the volume of the substance (V):

<u><em>d = m / V.</em></u>

d = 0.8787 g/ml.

V = 0.15 L x 1000 = 150 ml.

  • ∴ the mass of 0.15 L of benzene = d x V = (0.8787 g/ml) (150 ml) = 131.8 g.
5 0
3 years ago
For the reaction a2 + b2 → 2ab, ea(fwd) = 105 kj/mol and ea(rev) = 77 kj/mol. assuming the reaction occurs in one step, calculat
Lady bird [3.3K]
Answer is: 28 kJ.
Chemical reaction: A₂ + B₂ ⇄ 2AB.
Ea(forward) = 105 kJ/mol.
Ea(reverse) = 77 kJ/mol.
ΔH(reaction) = ?
<span>The enthalpy change of reaction is the change in the energy of the reactants to the products.
</span>ΔH(reaction) = Ea(forward) - Ea(reverse).
ΔH(reaction) = 105 kJ/mol - 77 kJ/mol.
ΔH(reaction) = 28 kJ/mol; this is endothermic reaction (ΔH <span>> 0).</span>

6 0
3 years ago
Complete this neutralization equation:<br> H2SO4 + Al(OH)3
elena-s [515]

Answer:

H2SO4 + Al(OH)3 = Al2(SO4)3 + H2O

Explanation:

4 0
4 years ago
A sample of 0.370 mol of a metal oxide (m2o3) weighs 55.45 g. how many grams of o are in the sample?
Wewaii [24]
0.370 mol metal oxide = 55.45 g 

<span>1 mol = 55.45/0.370 = 149.86 g </span>

<span>in 1 mol there are 3 mol O = 16 * 3 = 48 g of O </span>

<span>there is 48/149.86 * 100% O in the sample </span>

<span>the sample has 48/149.86 * 0.370 = 0.119 g O</span>
6 0
3 years ago
Can anyone answer this
mariarad [96]

Answer:

i have same problem bro or sis

Explanation:

5 0
3 years ago
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