Question

How many milliliters of a 0.223 M KNO3 solution contain 0.250 moles of KNO3?

Answer 1

Answer:

1121.08 millilitres of 0.223 M $KNO_{3}$ solution contains 0.250 moles of $KNO_{3}$.

Explanation:

The formula for molarity of a solution:

$Molarity=\frac{n}{V}\\ where,n=number\: of\:moles\\V=volume\:of\:solution\:in\:L$

Molarity = 0.223 M

n = 0.250 moles

$V=\frac{n}{Molarity}=\frac{0.250}{0.223}=1.12108L=1121.08mL$

Therefore, 1121.08 millilitres of 0.223 M  $KNO_{3}$ solution contains 0.250 moles of  $KNO_{3}$.