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marissa [1.9K]
3 years ago
11

Determine whether the given compound name or formula contains a polyatomic ion. N H 4 C l Choose... Magnesium sulfate Choose...

Sodium phosphide Choose... S O 3 Choose... Calcium hydroxide Choose... K C N Choose...
Chemistry
1 answer:
Morgarella [4.7K]3 years ago
4 0

Answer:

NH₄Cl, Magnesium sulfate, KCN

Explanation:

Determine whether the given compound name or formula contains a polyatomic ion.

  • NH₄Cl. YES. It contains the polyatomic ion ammonium NH₄⁺.
  • Magnesium sulfate. YES.  It contains the polyatomic ion sulfate SO₄²⁻.
  • Sodium phosphide Na₃P. NO.
  • SO₃. NO.
  • Calcium hydroxide Ca(OH)₂. NO.
  • KCN. YES. It contains the polyatomic ion cyanide CN⁻.
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4 years ago
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An aqueous sodium acetate, NaC2H3O2 , solution is made by dissolving 0.395 mol NaC2H3O2 in 0.505 kg of water. Calculate the mola
liq [111]

<u>Answer:</u> The molality of NaC_2H_3O_2 solution is 0.782 m

<u>Explanation:</u>

Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molality:

\text{Molality of solution}=\frac{\text{Moles of solute}}{\text{Mass of solvent (in kg)}} .....(1)

Given values:

Moles of NaC_2H_3O_2 = 0.395 mol

Mass of solvent (water) = 0.505 kg

Putting values in equation 1, we get:

\text{Molality of }NaC_2H_3O_2=\frac{0.395mol}{0.505kg}\\\\\text{Molality of }NaC_2H_3O_2=0.782m

Hence, the molality of NaC_2H_3O_2 solution is 0.782 m

8 0
3 years ago
All living things contain _________ in proteins, fats, and carbohydrates which can be recycled in various ways within an environ
Elodia [21]
All living things contain carbon
8 0
3 years ago
Read 2 more answers
A sample of Element X is found to contain 67.25% of isotope type 1 (85.91) and 32.75% of isotope type 2 (87.91). Calculate the a
KengaRu [80]

Answer:

The average atomic mass is 86.565

Explanation:

An element's average atomic mass is the sum of the products of the masses of the isotopes of the element and their percentage abundance divided by 100

The average atomic mass of the Element X is given as follows;

Isotope type 1 (85.91) ×

Isotope {}   Abundance (%)        Mass         /100        Portion of average mass

Type 1 {}             67.25       ×       85.91      ÷  100        57.774475

Type 2 {}            32.75       ×       87.91       ÷  100       28.790525

{}                                 Average atomic mass         =  86.565

The average atomic mass = 86.565.

5 0
3 years ago
Calculate the concentration of each species in a 0.240 m c6h5nh3cl solution.
amm1812
The solution for this problem is:
C6H5NH3Cl is a strong salt: C6H5NH3+ + Cl- C6H5NH3+ + H2O <-----> C6H5NH2 + H3O+ 
K = Kw/ Kb= 1.0 x 10^-14 / 3.8 x 10^-10= 2.6 x 10^-5 

=2.6 x 10^-5 = x^2 / 0.240-x 
x = [H3O+] = 0.00251 M 
pH = 2.60 is the concentration
8 0
3 years ago
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