<u>Answer:</u> The molality of
solution is 0.782 m
<u>Explanation:</u>
Molality is defined as the amount of solute expressed in the number of moles present per kilogram of solvent. The units of molarity are mol/kg. The formula used to calculate molality:
.....(1)
Given values:
Moles of
= 0.395 mol
Mass of solvent (water) = 0.505 kg
Putting values in equation 1, we get:

Hence, the molality of
solution is 0.782 m
Answer:
The average atomic mass is 86.565
Explanation:
An element's average atomic mass is the sum of the products of the masses of the isotopes of the element and their percentage abundance divided by 100
The average atomic mass of the Element X is given as follows;
Isotope type 1 (85.91) ×
Isotope
Abundance (%) Mass /100 Portion of average mass
Type 1
67.25 × 85.91 ÷ 100 57.774475
Type 2
32.75 × 87.91 ÷ 100 28.790525
Average atomic mass = 86.565
The average atomic mass = 86.565.
The solution for this problem is:
C6H5NH3Cl is a strong salt: C6H5NH3+ + Cl- C6H5NH3+ + H2O <-----> C6H5NH2 + H3O+
K = Kw/ Kb= 1.0 x 10^-14 / 3.8 x 10^-10= 2.6 x 10^-5
=2.6 x 10^-5 = x^2 / 0.240-x
x = [H3O+] = 0.00251 M
pH = 2.60 is the concentration