The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L
From the question given above, the following data were obtained:
Initial pressure (P₁) = 8.5 atm
Initial volume (V₁) = 24 L
Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K
Final pressure (P₂) = 13.5 atm
Final temperature (T₂) = 15 °C = 15 + 273 = 288 K
<h3>Final volume (V₂) =? </h3>
- The final volume of the gas can be obtained by using the combined gas equation as illustrated below:

Cross multiply
298 × 13.5 × V₂ = 204 × 288
4023 × V₂ = 58752
Divide both side by 4023

<h3>V₂ = 15 L </h3>
Therefore, the final volume of the gas is 15 L
Learn more: brainly.com/question/25547148
We know that the equation for density is:

where D is the density, m is the mass in grams, and V is the volume.
Given two of the variables, we can then solve for density:

So therefore, we now know that the density of carbon dioxide gas is 0.00196g/mL.
Answer:
50 gram calcium do you need
Explanation:
please make me brainlist answer
Answer:
<em>Answer Below</em>
Explanation:
Percent composition by element
<u>Element </u> <u>Symbol</u> <u>Mass Percent</u>
Aluminium <u>Al</u> 34.590%
Hydrogen <u>H</u> 3.877%
Oxygen <u>O</u> 61.533%
Answer:
I think a red flower with one part colored yellow
Explanation: