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Ber [7]
3 years ago
6

Calculate the weighted average

Chemistry
1 answer:
padilas [110]3 years ago
3 0
Of what?
Attach a link or pic 
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The technetium-99 nuclide radioactively decays by beta emission. write a balanced nuclear chemical equation that describes this
nekit [7.7K]
Tc-99m<span> is a </span>metastable  isomer<span> of </span>Tc-99. It finds widespread applications in <span>medical diagnostic procedures.
</span>
Tc-99 is also a radioactive element. It's half-life is 2,11,000 years. Upon radioactive decay, it emits beta particles and gets converted into stable compound Ruthenium-99

This process of radioactive decay is shown below.
99 43Tc    →       99 44Ru     +     0 -1e
                            (stable)           (β particle)
7 0
3 years ago
Balance the following equation: H20 --&gt; H2 + O2​
MakcuM [25]

2H2O = 2H2 + O2.

<h3><u>Explanation</u>:</h3>

Balancing equations is very essential because of the fact that it represents the stoichiometric quantities of the reactants needed to react to form the product. The ratio of the weights of reactant and product are also very well understood from this.

Here in this equation, the water is broken into hydrogen and oxygen. The balanced reaction is

2H2O = 2H2 + O2.

Two moles of water is broken down into 2 moles of hydrogen and one mole of oxygen.

5 0
3 years ago
Which increases the likelihood that a dead organisms will be fossilized
zzz [600]
When an organism is buried quickly there is less decay and better the chance for it to be persevere. The hard parts of the organism such as bones, shells, and teeth have a better chance of becoming fossils that softer parts of the organism. HARD BONES.
6 0
2 years ago
Calculate the energy, in joules, required to ionize a hydrogen atom when its electron is initially in the n =2 energy level. The
qaws [65]

Answer:

E_{ionization}=5.45\times 10^{-19}\ J

Explanation:

E_n=-2.18\times 10^{-18}\times \frac{1}{n^2}\ Joules

For transitions:

Energy\ Difference,\ \Delta E= E_f-E_i =-2.18\times 10^{-18}(\frac{1}{n_f^2}-\frac{1}{n_i^2})\ J=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J

\Delta E=2.18\times 10^{-18}(\frac{1}{n_i^2} - \dfrac{1}{n_f^2})\ J

So, n_i=2 and n_f=\infty (As the hydrogen has to ionize)

Thus,

\Delta E=2.18\times 10^{-18}(\frac{1}{2^2} - \dfrac{1}{{\infty}^2})\ J

\Delta E=2.18\times 10^{-18}(\frac{1}{2^2})\ J

E_{ionization}=5.45\times 10^{-19}\ J

4 0
3 years ago
Write your name on a piece of paper with a water soluble marker and place the slime on top of it and remove very quickly before
creativ13 [48]
Uh i did this because it made me curious... i may have done it wrong nothing happened
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3 years ago
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