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3 years ago

What is 672,905 rounded to the nearest ten thousand

Mathematics

1 answer:

ZanzabumX [31]3 years ago

8 0

Answer:

670,000

Step-by-step explanation:

5 or more, raise the score.

4 or less, let it rest.

5 rounds 0 up to 1

672,910

1 doesn't change the 9

672,900

9 rounds 2 up to 3

673,000

3 doesn't change the 7

670,000

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Transform the kilometers into percentages pls

bazaltina [42]

Percentages? Are you sure that’s not a mistake

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3 years ago

Stacey is making candles to sell at the craft fair. She has 5 pounds of wax to make the candles. She needs 18 pound of wax for 1

SIZIF [17.4K]

Answer:

Step-by-step explanation:

To determine how much wax you will need, you will first need to decide on ... (ounces needed) ÷ 16 (ounces in 1 pound) = (pounds of wax needed). For example, let's say you wanted to make 25 candles in our 8 oz Candle Tins ... 5 x 25 = 125 oz of wax ... It's always better to have a little wax left over than to not have enough!

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3 years ago

based on the simulation, what is the probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to

Triss [41]

Using the binomial distribution, supposing that 0.3 of the callers have to wait more than 8 minutes to have their calls answered, it is found that there is a 0.3828 = 38.28% probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to have their calls answered.

For each caller, there are only two possible outcomes, either they have to wait more than 8 minutes to have their calls answered, or they do not. The probability of a caller having to wait more than 8 minutes is independent of any other caller, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.
n is the number of trials.
p is the probability of a success on a single trial.

In this problem:

10 callers, hence $n = 10$
Suppose that 0.3 of them have to wait more than 8 minutes, hence $p = 0.3$

The probability that <u>at most 2</u> of the next 10 callers will have to wait more than 8 minutes is:

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)$

Then

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.3)^{0}.(0.7)^{10} = 0.0282$

$P(X = 1) = C_{10,1}.(0.3)^{1}.(0.7)^{9} = 0.1211$

$P(X = 2) = C_{10,2}.(0.3)^{2}.(0.7)^{8} = 0.2335$

Then:

$P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0282 + 0.1211 + 0.2335 = 0.3828$

0.3828 = 38.28% probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to have their calls answered.

A similar problem is given at brainly.com/question/25537909

3 0

3 years ago

Which list is in order from least to greatest?

adell [148]

They would be 1.94, 1.25, 6, 8.1!

Hope it help!

-John

3 0

4 years ago

Read 2 more answers

If tan theta= 15/8, then:

Maurinko [17]

Hello there!

The only thing we have to do here is remember our trigonometric functions!

sin=y/r
cos=x/r
tan=y/x
sec=r/x
csc=r/y
cot=x/y

Knowing that tanᎾ=15/8, we know that y=15 and x=8

Now we need to look at the answer choices and see if they are correct.

A. secᎾ=17/8
Since secᎾ=r/x and r=17 and x=8, this is correct.

B. cosᎾ=15/17
Since cosᎾ=x/r and x=8 and r=17, this is wrong.

C. cotᎾ=8/15
Since cotᎾ=x/y and x=8 and y=15, this is also correct!

D. cscᎾ=17/15
Since cscᎾ=r/y and r=17 and y=15, this is right too.

I really hope this helps!
Best wishes :)

5 0

3 years ago

Read 2 more answers