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elena55 [62]
3 years ago
8

PLEASE HELP

Mathematics
1 answer:
melisa1 [442]3 years ago
4 0

Step-by-step explanation:

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10.4 sweets cost 28p altogether,<br> how much much do 7 sweets cost
Serjik [45]
28/10.4=2.69
2.69*7=18.83
7 0
3 years ago
Read 2 more answers
Find the distance between 6.2 and<br> -4.3 on a number line.
Nitella [24]

Answer:

The two given numbers are 10.5 units apart.

Step-by-step explanation:

Subtract the smaller from the larger.  The larger number here is 6.2. Then we have

6.2 - (-4.3) = 6.2 + 4.3 = 10.5

The two given numbers are 10.5 units apart.

8 0
3 years ago
Ratio of width to length is 2:3 if the length 18 meters what is the width
weeeeeb [17]

Answer:

12

Step-by-step explanation: 18/3=6 6(2)= 12

8 0
3 years ago
How many solutions are possible for a system of equations containing exactly one linear and one quadratic equation? (Select all
galina1969 [7]
Remember that a quadratic equation is a parabola. The equation is of the type y = Ax^2 + Bx + C


A linear equation is a straight line. The equation is of the type y = MX + N


The soluction of that system is Ax^2 + Bx + C = MX + N

=> Ax^2 + (B-M)x + (C-N) = 0


That is a quadratic equation.


A quadratic equation may have 0, 1 or 2 real solutions. Those are all the possibilitis.


So you must select 0, 1 and 2.


You can also get to that conclusion if you draw a parabola and figure out now many point of it you can intersect with a straight line.


You will realize that depending of the straight line position it can intersect the parabola in none point, or one point or two points.  
6 0
3 years ago
If you had carried out the algebra using variables before plugging numbers into your expressions, you would have found that (vf)
SashulF [63]

Answer:

Step-by-step explanation:

Volt is energy per electric charge

1V=1J/C

and the energy units in terms of meters, seconds and kilograms are:

1J= 1kg\frac{m^{2}}{s^{2}}

So the unit of volt is

1V= kg \frac{m^{2}}{Cs^{2}}

So the velocity expression (it can not be read completly) but i guess that it could be as follows

vf_{a} = -2\sqrt{\frac{q_{a}\Delta V}{m_{a}}}

So the unit analysis would be

vf_{a} = \sqrt{\frac{C kg\frac{m^{2}}{Cs^{2}}}{kg}}}

note that the coulomb unit of numerator is cancelled from the denominator. The same occurs for kg unit.

vf_{a} = \sqrt{\frac{m^{2}}{s^{2}}}

Applying square root

vf_{a} = \frac{m}{s}

7 0
3 years ago
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