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Aleksandr [31]
3 years ago
13

Find the difference of 25 and 0.88

Mathematics
2 answers:
Katen [24]3 years ago
5 0

Answer:

25 is a number (odd)  0.88 is a decimal

Step-by-step explanation:

Fed [463]3 years ago
4 0

Answer:

24.12

Step-by-step explanation:

The term 'difference' implies subtraction.

25 - 0.88 = 24.12

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Rearrange the formula A = <br> Θr2<br> 2<br> for Θ.
Lina20 [59]

Answer:

\theta=\frac{2A}{r^2}

Step-by-step explanation:

Given : The formula A=\frac{\theta r^2}{2}

We have to rearrange the given formula for \theta

Consider the given formula A=\frac{\theta r^2}{2}

Multiply both side by 2, we have,

2A={\theta r^2

Divide both side by r^2 , we have,

\frac{2A}{r^2}= \frac{\theta r^2}{r^2}

Simplify, we get,

\frac{2A}{r^2}=\theta

Thus, \theta=\frac{2A}{r^2}  

3 0
3 years ago
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If two polygons are similar, they are congruent.<br> Always true sometimes true or never true?
charle [14.2K]

Answer:

It is true.

Step-by-step explanation:

congruent polygons have the exact same size and are a perfect match because all corresponding parts are congruent (equal). ... This means that if two polygons are similar, then their corresponding angles are congruent

5 0
3 years ago
Draw two lines that are perpendicular. What type of angle is formed where the perpendicular lines intersect?
Vladimir79 [104]

a right angle (90 degrees)

4 0
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X + y = 8<br> 3x - y = 12
Virty [35]

Answer:

x = 5 and y = 3

Step-by-step explanation

y crosses out so you are left with

4x = 20 (divide by 4)

x = 5

plug x into either equation

5 + y = 8 (subtract 5)

y = 3

7 0
3 years ago
Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a
Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

P(X

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

P(X=x)=\lambda e^{-\lambda x}

The cumulative distribution for this function is given by:

F(X) = 1- e^{-\lambda x}, x\ geq 0

We know the value for the mean on this case we have that :

mean = \frac{1}{\lambda}

\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48

At most 3 hours?

P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: Var(X) =\frac{1}{\lambda^2}

And the deviation would be:

Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725

And the mean is given by Mean = 2.725

Two deviations correspond to 5.540, so we want this probability:

P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

P(X

8 0
3 years ago
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