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Colt1911 [192]
3 years ago
12

Draw the two major products obtained when 3,3,6-trimethylcyclohexene is treated with NBS and irradiated with UV light.

Chemistry
1 answer:
svetoff [14.1K]3 years ago
6 0

Answer:

Attached is the diagram

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What is the concentration of H+ ions at a pH = 11?
natta225 [31]

Answer:

\huge 1 × {10}^{-11} \: \: M

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ {H}^{+} ]

Since we are finding the H+ ions we find the antilog of the pH

So we have

11 =  -  log({H}^{+})  \\ {H}^{+} =  {10}^{ - 11}

We have the final answer as

1 × {10}^{-11} \: \: M

Hope this helps you

6 0
3 years ago
Briefly discuss interpretations of your observations and results. Discuss how your observations illustrated LeChatelier's princi
Dvinal [7]

Answer:

Le Chatelier's principle can be applied in explaining the results

Explanation:

According to Le Chatelier's principle, when a constraint such as a change in concentration in this case is imposed on a chemical system in equilibrium, the system will adjust itself in such a way as to annul the constraint imposed.

Hence, when the color of the solution was more like that of the control, the reaction would shift towards the left. Similarly, when the color was more like it was towards the reactant, the reaction would shift towards the right.

If we were to prepare calcium oxalate, we should prepare it in a base solution. This is because when the base was added to calcium oxalate, it did not form any precipitate but when an acid was added to the calcium oxalate, it formed a precipitate.

4 0
3 years ago
2 or 1 fun facts about preventing hazardous waste
Sedbober [7]

Answer:

Not really fun facts about hazardous waste

Explanation:

four characteristics of hazardous waste are: ignitability • corrosivity • reactivity • toxicity. These things should be thrown away a proper way to reduce pollution.

6 0
3 years ago
Which is and element <br> A) Salad<br> B) Sugar<br> C) Water <br> D) Potassium
Semenov [28]

Answer:

the only element above is potassium

3 0
4 years ago
1) If 0.193 grams of toluene is dissolved in 2.532 grams of p-xylene, what is the molality of toluene in the solution?2) If a fr
AveGali [126]

Answer:

The value of K_f for xylene is 4.309°C/m.

The molar mass of pentane using this data is 73.82 g/mol.

Explanation:

\Delta T_f=K_f\times \frac{\text{Amount of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent(kg)}}

where,

\Delta T_f =depression in freezing point

K_f = freezing point constant  

we have :

1) freezing point constant  for xylene = K_f =?

Mass of toluene = 0.193 g

Mass of xylene = 2.532 kg = 0.002532 kg ( 1 g =0.001 kg)

\Delta T_f=3.57^oC

3.57^oC=K_f\times \frac{0.193 g}{92 g/mol\times 0.002532 kg}

K_f=4.309^oC/m

The value of K_f for xylene is 4.309°C/m.

2)

Mass of pentane = 0.123 g

molar mass of pentame= M

Mass of xylene = 2.493 g =  0.002493 kg

Freezing point Constant of xylene = K_f=4.309^oC/m

2.88^oC=4.309^oC/m\times \frac{0.123g}{M\times 0.002493 kg}

M = 73.82 g/mol

The molar mass of pentane using this data is 73.82 g/mol.

5 0
3 years ago
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