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3 years ago

Collisions app covalent bonding level 15

Chemistry

2 answers:

Maksim231197 [3]3 years ago

7 0

Answer:

What is this? I am confused.

Explanation:

Anna [14]3 years ago

7 0

Answer: change the nitrogen with oxygen for the first part then have the nitrogens collided instead of oxygens in the last part - not sure if my terminology is correct but here is the pic to show!

Explanation:

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Iron has many isotopes but only 4 are found in significant amounts in naturally found mixtures. The amounts by mass percent are:

AnnZ [28]

Answer:

The average mass of iron to be is 54.76 amu.

Explanation:

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

Mass of Fe-54 isotope = 53.9396 amu

Percentage abundance of Fe-54 = 5.845%

Fractional abundance of Fe-54 = 0.05845

Mass of Fe-56 isotope = 55.9349 amu

Percentage abundance of Fe-56 = 91.754 %

Fractional abundance of Fe-56= 0.91754

Mass of Fe-57 isotope = 56.9354 amu

Percentage abundance of Fe-57 = 2.119%

Fractional abundance of Fe-57 = 0.002119

Mass of Fe-58 isotope = 57.9333 amu

Percentage abundance of Fe-58 = 0.282%

Fractional abundance of Fe-58 = 0.00282

Average atomic mass of iron :

$=53.9396 amu\times 0.05845+55.9349 amu\times 0.91754 +56.9354 amu\times 0.002119 + 57.9333 amu\times 0.00282=54.76 amu$

The average mass of iron to be is 54.76 amu.

5 0

3 years ago

How many moles of nitrate are dissolved in water if 6.15 mole strontium nitrate dissolve?

pashok25 [27]

The number of moles of nitrate dissolved in water if 6.15 mole of strontium nitrate is : 12.3 moles

<u>Given data :</u>

Moles of strontium nitrate = 6.15 moles

<h3>Ionization of Strontium Nitrate </h3>

When strontium nitrate ( $Sr(NO_{3} )_{2}$ ) is placed in water it will dissociates into its ions because strontium nitrate is an ionic compound.

Next step : Represent the ionization of strontium nitrate

$Sr ( NO_{3} )_{2} (aq) --- > Sr^{2+} (aq) + 2NO_{3} ^{-} (aq)$

From the Stoichiometry of the chemical reaction

I mole of strontium nitrate = 2 moles of Nitrate ions

6.15 mole of strontium nitrate = 2 * 6.15

= 12.3 moles of Nitrate

Hence we can conclude that The number of moles of nitrate dissolved in water if 6.15 mole of strontium nitrate is : 12.3 moles.

Learn more about Stoichiometry of chemical reaction : brainly.com/question/27058367

3 0

3 years ago

Tumu’s class was given an assignment to feature a scientist that contributed to the development of the cell theory. The class de

xxMikexx [17]

Answer:

The types of cells at work in the human body

Explanation:

Rudolf Virchow was a German physician who is known as the father of modern pathology. He contributed to the development of the cell theory by concluding that all cells come from preexisting cells. This led to the conclusion that diseases occur at the cellular level, which allowed scientists to diagnose diseases more accurately.

Considering that Virchow analyzed human cells, the image that Tumu would be most likely to use in his assignment is the one of the types of cells at work in the human body.

4 0

3 years ago

Read 2 more answers

For an ideal gas condition, what is the mass (g) of N2 if the pressure is 2.0 atm, the volume is 25 mL and the temperature is 29

Alchen [17]

Answer:

THE MASS OF NITROGEN GAS IN THIS CONDITIONS IS 0.0589 g

Explanation:

In an ideal condition

PV = nRT or PV = MRT/ MM where:

M = mass = unknown

MM =molar mass = 28 g/mol

P = pressure = 2 atm

V = volume = 25 mL = 0.025 L

R = gas constant = 0.082 L atm/mol K

T = temperature = 290 K

n = number of moles

The gas in the question is nitrogen gas

Molar mass of nitrogen gas = 14 * 2 = 28 g/mol

Then equating the variables and solving for M, we have

M = PV MM/ RT

M = 2 * 0.025 * 28 / 0.082 * 290

M = 1.4 / 23.78

M = 0.0589 g

The mass of the nitrogen gas at ideal conditions of 2 atm, 25 mL volume and 290 K temperature is 0.0589 g

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4 years ago

What would be the new volume if the pressure on 600 mL is increased from 90 kPa to 150 kPa?

Karolina [17]

Explanation:

What would be the new volume if the pressure on 600 mL is increased from 90 kPa to 150 kPa? V = Pu V₂ = 360 mL ~ 400 mL 6.

6 0

3 years ago