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stich3 [128]
1 year ago
12

Convert the following measurement

Chemistry
1 answer:
KiRa [710]1 year ago
6 0

Answer:

9.9 x 10^-2 g*cm²/s²

Explanation:

9.9 × 10^-9 kg*m²/s² =    g*cm²/s²

1 kg*m²/s² = 1 joule(s)

1 g*cm²/s² = 1 erg(s)

britannica

1 kg = 1000g = 1x10^3 g

1 m²= 10000 cm² = 1x10^4 cm²

add the exponents 3 and 4 which = 7

-9 + 7 = -2

9.9 × 10^-9 kg*m²/s² = 9.9 x 10^-2 g*cm²/s²

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5 0
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8 0
4 years ago
If it requires 37.5 mL of a 0.245 M HBr solution to neutralize 18.0 mL Mg(OH)2, what is the concentration of the Mg(OH) 2 soluti
xenn [34]
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M1V1 = M2V2
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9.1875 = (M2)(18.0 mL)
9.1875/(18.0 mL) = (M2)(18.0 mL)/(18.0 mL)
0.51041
this is not the complete answer as the mol to mol ratio must be considered!
For every 2 mols of HBr there is 1 mole of <span>Mg(OH)2; ratio = 2:1
</span>0.51041 / 2 = 0.25520
M2 = 0.25520
0.25520 M of<span> Mg(OH)2 solution</span>
7 0
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Which element has a total of 32 protons
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5 0
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