Question

Dont have to answer all but with whatever you can will help, thank you. Scenario

Answer 1

Answer:

a.H = gt2/2.

b  t = (2H/g)1/2

c.D = vt,

D = v (2H/g)^1/2

Explanation:

Dont have to answer all but with whatever you can will help, thank you. Scenario

A rock is thrown horizontally with speed v from the top of a cliff of height H,

as shown in the diagram to the right.

Using Representations

PART A: On the diagram, choose a location for a horizontal and vertical origin. Label

your choice with x = 0 and y = 0 on the diagram. Choose a horizontal and

vertical positive direction and label those directions on the diagram using

arrows.

Quantitative Analysis

PART B: Identify an equation that can be used to solve for the time it takes the rock to hit the ground. Write

the equation below. (If you're having trouble finding the right equati

the bottom of the cliff, the ground, and the water are at the same level (this was not stated clearly in the problem). An assumption although

(a)

If there is no air resistance,

from newton's equation of motion, we can say that

s=ut+1/2gt^2

s=H, the height of the rock to the ground level

a=g

u=0, the initial velocity for vertical motion

t is the time of flight it took the rock from the origin ,then through the projectile path down to the ground

H = gt^2/2.

where

t = time

g = acceleration of gravity

(b)  from equation a, we can make t the subject of the equation

t = (2H/g)1/2

(c)

D = vt,  

t=d/v

with t computed in part (b).

(d)

D = v (2H/g)1/2

Answer 2

Answer:

Explanation:

A) The origin of the coordinate system could be at the position where the rock leaves the hand of he person throwing the rock.

B) $H = \frac{1}{2}gt^2$

C) $t=\sqrt{\frac{2H}{g} }$

D) $D=v_ot$

E) Use equation from part C and substitute for time t in equation from part D:

$D=v_0\sqrt{\frac{2H}{g}}$