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MrRissso [65]
3 years ago
13

A Force of 20N displaces a body about 45m how much work is done?​

Physics
2 answers:
Neporo4naja [7]3 years ago
8 0
159 is how much work is done to the body.
Orlov [11]3 years ago
7 0

Answer:

159 ofc

Explanation:

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If a car's engine gives off 65% thermal energy, what is the maximum efficiency?
stich3 [128]

Answer:

35%

Explanation:

The car's engine gives off 65% thermal energy

So only 35 % is converted into mechanical energy .

input heat = Q₁ = 100

output heat = Q₂ = 65

Work output = Q₁ - Q₂ = W

W = 100 - 65 = 35

Efficiency = W / Q₁ X 100

= (35/ 100) X 100

= 35%.

5 0
3 years ago
26. An ice-skater who weighs 200 N is gliding across the ice. If the force of friction is 4 N. what is the
Scrat [10]

Answer:

0.02

Explanation:

coefficient of kinetic friction = μ

force of friction = Ff

Normal Force = FN, but

FN = -W

Ff = -μFN

so μ = Ff/FN

= 4N/200N

= 0.02.

7 0
3 years ago
What is simple machine<br>​
notsponge [240]

Answer:

ϟ \huge{ \boxed{ \purple{ \text{Simple \: Machine}}}}

⤥ We use different types of devices in our life to make our work easier. A spade is used to dig , a broom is used to sweep , a hammer is used to pass a nail on the wall and a plank is used to drag a load up to a certain height. All these simple things or devices , which are used in our daily life are called simple machines. Such simple machines do not do our work themselves but we have to use force on them to work with them. Thus , Simple machines are those tools or devices which make our work easier and convenient to do in the direction of force.

Hope I helped ! ッ

Have a wonderful day / night ♡

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

7 0
3 years ago
Read 2 more answers
An electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric
8090 [49]

Answer:

1.) 11 km/s

2.) 9.03 × 10^-5 metres

Explanation:

Given that an electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C.

Electron q = 1.6×10^-19 C

Electron mass = 9.11×10^-31 Kg

(a) What is the speed of the electron 1.3 ns after entering this region?

E = F/q

F = Eq

Ma = Eq

M × V/t = Eq

Substitute all the parameters into the formula

9.11×10^-31 × V/1.3×10^-9 = 48 × 1.6×10^-19

V = 7.68×10^-18 /7.0×10^-22

V = 10971.43 m/s

V = 11 Km/s approximately

(b) How far does the electron travel during the 1.3 ns interval?

The initial velocity U = 64 km/s

S = ut + 1/2at^2

S = 64000×1.3×10^-6 + 1/2 × 8.4×10^12 × ( 1.3×10^-9)^2

S =8.32×10^-5 + 7.13×10^-6

S = 9.03 × 10^-5 metres

3 0
3 years ago
(a) Two point charges totaling 8.00 μC exert a repulsive force of 0.150 N on one another when separated by 0.500 m. What is the
Anastaziya [24]
3 is jxhuneuxndnzixbf
7 0
3 years ago
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