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boyakko [2]
3 years ago
15

Alhondro wants to determine the average shoe size of all of male students in his school

Mathematics
1 answer:
Arada [10]3 years ago
8 0
We need the rest of the question
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The volume of a sphere whose diameter is 18 centimeters is how many cubic centiemters
Arturiano [62]

Answer:

3053.63 cm^3

Step-by-step explanation:

Volumme of a sphere =  \frac{4}{3}\pi*r^3.

We do not have the radius of the sphere, but we have its diameter.

We know that there is a relationship between radius and diameter.

d = 2r\\r = \frac{d}{2}

Then the formula of the volume of a sphere according to its diameter is:

\frac{4}{3}\pi (\frac{d}{2}) ^ 3\\\\\frac{4}{3}\pi(9)^3 = 972\pi = 3053.63 cm^3\\\\

3 0
3 years ago
If mBDE = 125 what is mGDF? A) 35. B) 45. C) 55. D) 65
joja [24]
A supplmentary angle = 180°

∠BDE and ∠BDF are vertical angles, and so are congruent.

∠BDF = 125°, because ∠BDF ≅ ∠BDE.

∠CDA ≅ ∠EDF

∠CDA = 90°


<span>line BJ </span> is angle bisector of ∠CDA. ∠CDB is 1/2 of ∠CDA

∠CDA = 90°

∠CDB = 90/2
∠CDB = 45°

∠GDF is a vertical angle of ∠CDB, and it's measurement will be the same as ∠CDB.

∠GDF ≅ ∠CDB
∠CDB = 45°
∠GDF  = 45°


∠GDF  = 45° should be your answer

hope this helps
7 0
3 years ago
Read 2 more answers
solve this using pythagorean theorem please and give me the right answer and i will give YOU brainliest and a like in return.
Dima020 [189]

Answer:

6.8 miles

Step-by-step explanation:

a^2+b^2=c^2

4 0
1 year ago
Mr. Harry had 4 daughters, each daughter had a brother. How many Children does Mr. Harry have? ​
irga5000 [103]

Answer:

Mr. Harry has 5 children.... I know what you were going for...

5 0
2 years ago
We select n + 1 different integers from the set { 1 , 2 , ··· , 2 n } . Provethat there will alwaysbe two among the selected inte
just olya [345]

Answer:

See answer below

Step-by-step explanation:

From the set

{1,2,3,4...2n} we have 2n numbers in total , n are odd and n are even , therefore for a sample of n+1 numbers , we have at least 1 even number and 1 odd number.

Then

it the set includes 1 , the largest common divisor is 1 for 1 and the other numbers

if the set includes 3, there will be always a number that is not divisible by 3. Even we construct a set of n+1 numbers that are multiple of 3 , the largest number would be 3*(n+1)= 3*n+3 > 2*n (out of bounds) , therefore we are forced to take other number that is not divisible by 3  → the largest common divisor of that number with 3 is 1

If the set includes any other prime number → the largest common divisor of that with any other is 1

For the remaining odd numbers N, they can be factorised into other 2 odd common divisors N₂ and n₂ :

N = N₂*n₂ , since n₂ ≥ 2 →  N₂ < N

then the even N₂ also should be contained in the set

therefore also for N₂

N = N₃*n₃ →  N₃ < N₂

therefore if we continue , we would obtain a number  even Nn that has no smaller common divisors → since we cannot take all the multiples of N min ( because Nmin*(n+1)= Nmin*n+Nmin > 2*n for Nmin≥2) → there is at least a number in the sample of n+1 integers whose largest common divisor is 1

6 0
3 years ago
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