HELPPPP PLZZZzzzzzzzz

A bus left town K

sukhopar [10]

Answer:

2 and half hour they will at T town

3 0

3 years ago

Read 2 more answers

Plz Answer this question ASAP!

nydimaria [60]

Answer:

$564$ tiles

Step-by-step explanation:

there are many ways to solve this soo...

1. convert to centimetres (there are 100 centimetres in 1 metre)

2. the square tiles area = $20*20=400cm$

2. find the large area (4.8m x 3.8m or 480cm x 380cm)

$480 *380=182400cm$

2. find the two smaller areas (1.2m x 1.8m or 120cm x 180cm)

$2(120*180)=4.3200cm$

3. add to find total area

$182400 +43200=225600cm$

4. find how many tiles are needed

$\frac{225600}{400}= 564$ tiles

8 0

3 years ago

Ex 7 Mrs. Phillips has 10 identical cans without labels. She knows that she had 1 can of peas, 5 cans of corn, 1 can of carrots,

zubka84 [21]

Yo bro I just didn’t read your message yet what I was saying that was the sun I love the way that is a beautiful day and I love 103820482

5 0

3 years ago

I DON’T UNDERSTAND! PLEASE HELP!

Brums [2.3K]

Answer:

The height of the water is $60.5\ ft$

Step-by-step explanation:

step 1

Find the volume of the tank

The volume of the inverted right circular cone is equal to

$V=\frac{1}{3}\pi R^{2} H$

we have

$R=16\ ft$

$H=96\ ft$

substitute

$V=\frac{1}{3}\pi (16)^{2} (96)$

$V=8,192\pi\ ft^{3}$

step 2

Find the 25% of the tank’s capacity

$V=(0.25)*8,192\pi=2,048\pi\ ft^{3}$

step 3

Find the height, of the water in the tank

Let

h ----> the height of the water

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional

$\frac{R}{H}=\frac{r}{h}$

substitute

$\frac{16}{96}=\frac{r}{h}\\ \\r= \frac{h}{6}$

where

r is the radius of the smaller cone of the figure

h is the height of the smaller cone of the figure

R is the radius of the circular base of tank

H is the height of the tank

we have

$V=2,048\pi\ ft^{3}$ -----> volume of the smaller cone

substitute

$2,048\pi=\frac{1}{3}\pi (\frac{h}{6})^{2}h$

Simplify

$221,184=h^{3}$

$h=60.5\ ft$

6 0

3 years ago

Scores for a common standardized college aptitude test are normally distributed with a mean of 493 and a standard deviation of 9

Tomtit [17]

Answer:

34.01% probability that his score is at least 532.1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 493, \sigma = 95$