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Serhud [2]
2 years ago
14

What are the two smallest consecutive odd integers whose sum is greater than 17

Mathematics
1 answer:
Mice21 [21]2 years ago
5 0

Answer:

9 and 11

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
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Someone please help i dont know how to solve for 6 and 7 <br> :(
Sphinxa [80]

If I remember correctly, the solutions are only on the solid line or in the shaded area? therefore Answers could be:

6.) (-3,0.5) (-4,0) (-2,0) (-2,-5) (-3,-5) (-4,-1) (-3,-1) (-2,-1)

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7 0
2 years ago
The sum of 5 consecutive odd numbers is 145.
Anna007 [38]
Let x be the first odd integer. x + 2 the second x + 4 the third x + 6 the fourth x + 8 the fifth. add them up and you get 5x + 20 set 5x + 20 = 145 and solve for x. 5x=145-20 5x=125 x=25 answer=25,27,29,31,33
7 0
3 years ago
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Find the surface area of the cube shown.<br> (_________) square centimeters
Step2247 [10]

Answer:

The answer is: 181.5 square centimeters.

Step-by-step explanation:

The cube has six faces, and each face is a square with sides of length 5.5, so the area of one of this faces is 5.5^2=30.25, adding the six faces, we get the answer: A=6\times 30.25=181.5

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What is mZ1?<br> 490<br> 470<br> m21
zalisa [80]

490

Step-by-step explanation:

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