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Serhud [2]
2 years ago
14

What are the two smallest consecutive odd integers whose sum is greater than 17

Mathematics
1 answer:
Mice21 [21]2 years ago
5 0

Answer:

9 and 11

Step-by-step explanation:

You might be interested in
how much does britney need to buy 2 pearl bracelets and 2 emerald rings emerald ring price 6,395.00 Pearl bracelets prince 5,314
sineoko [7]
6,395.00 x 2 = 12,790

So $12,790 for the emerald rings.


5,314.00 x 2 = 10,628

So $10,628 for the pearl bracelets.

12,790 + 10,628 = 23,418

So $23,418.00 for all four pieces of jewelry.
Hope it helps!


7 0
3 years ago
Read 2 more answers
How many integers between 100 and 999 (inclusive) have distinct digits
daser333 [38]

Answer:

648

Step-by-step explanation:

Running this in Python, with the code as follows,

import math

cur_numbers = [0] * 3

num = 0

for i in range(100, 1000):

   cur_numbers[2] = i % 10

   i = math.floor(i/10)

   cur_numbers[1] = i % 10

   i = math.floor(i/10)

   cur_numbers[0] = i % 10

   if(len(set(cur_numbers)) == 3):

       num += 1

       print(cur_numbers)

       

print(num), we get 648 as our answer.

Another way to solve this is as follows:

There are 9 possibilities for the hundreds digit (1-9). Then, there are 10 possibilities for the tens digit, but we subtract 1 because it can't be the 1 same digit as the hundreds digit. For the ones digit, there are 10 possibilities, but we subtract 1 because it can't be the same as the hundreds digit and another 1 because it can't be the same as the tens digit. Multiplying these out, we have

9 possibilities for the hundreds digit x 9 possibilities for the tens digit x 8 possibilities for the ones digit  = 648

5 0
2 years ago
Factor the expression completely I’ve the complex numbers X^4+10x^2+25
Elza [17]

We have

(a + b)² = a² + 2ab + b²

so that with a = x² and b = 5, we have

x⁴ + 10x² + 25 = (x² + 5)²

Next, we have

a² - b² = (a - b) (a + b)

so that with a = x and b = √5 i,

x² + 5 = x² - (-5) = (x - √5 i) (x + √5 i)

So, the complete factorization over the complexes is

(x - √5 i)² (x + √5 i)²

5 0
2 years ago
How does the graph of g(x)=1/x-5. +2 compare to the graph of the parent function f(x)=1/x
malfutka [58]

Answer:

x value of vertical asymptote and y value of horizontal asymptote

Step-by-step explanation:

The graph of 1/x approaches infinity as x approaches 0 (the vertical asymptote)

As x gets either bigger or smaller, 1/x approaches the x-axis (from above on the positive side, from below on the negative side) (the horizontal asymptote)

Consider 1/(x-5) + 2, at what value of x does the graph 'go nuts' ?

When the bottom of the fraction becomes 0, x - 5 becomes 0 when x = 5, so the vertical asymptote of g(x) is at x=5

What value of y does f(x) approach as x gets more positive or more negative - as x gets bigger (as an example), y approaches 0

What y value does g(x) approach as x gets bigger?  Well, as x gets big, 1/(x-5) gets small, approaching 0.  The smallest 0 + 2 can get is 2, so y=2 is the horizontal asymptote

8 0
3 years ago
Write a rule for the linear function with the following description: the graph contains the points (3,-2) and (3,0),
Maslowich

Answer:

x - 3 = 0

Step-by-step explanation:

You can realise it plotting the points.

Or you can use : ( x - x1 ) / ( y - y1 ) = ( x1 - x2 ) / ( y1 - y2 )

where ( x1 , y1 ) and ( x2 , y2 ) are the given points.

3 0
2 years ago
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