R = { (x,y): 3x-y=0 }
The condition is 3x=y so that's not going to be any of these things.
R is reflexive if (x,x)∈R for all x. Let's check.
3x - y = 3x - x = 2x ≠ 0 necessarily. NOT REFLEXIVE
R is symmetric if (x,y)∈R → (y,x)∈R. Let's check.
(x,y)∈R so
3x-y = 0
y = 3x
Is (y,x)∈R. That would be true if 3y-x=0
3y - x = 3(3x) - x = 8x ≠ 0 necessarily NOT SYMMETRIC
R is transitive if (x,y)∈R and (y,z)∈R → (x,z)∈R. Let's check.
3x-y = 0 so y=3x
3y-z = 0 so z=3y = 9x
3x - z = 3x - 9x = -6x ≠ 0 necessarily NOT TRANSITIVE
Answer:
you did not give us choices.
Step-by-step explanation:
Answer:
3^(n+1) - 3^n / 3^(n-1) = 6
(x² + 16)(x² - 16)
= (x²)² - 16²
= x⁴ - 256
Answer:
p - 19
Step-by-step explanation:
multiply the bracket by -2*2(-4) , -4p - 16 - 3 +5p , 5p - 4p= p & -3 - 16=-19
so exp is p - 19
